Problem:

How many moles of ethane are required to produce 22g CO2 after combustion?

Solution:

To determine the number of moles of ethane required to produce 22g of CO2 after combustion, we need to consider the balanced chemical equation for the combustion of ethane.

1. Balanced Chemical Equation:
The balanced chemical equation for the combustion of ethane is as follows:
C2H6 + O2 → CO2 + H2O

From the equation, we can see that one mole of ethane (C2H6) reacts with three moles of oxygen (O2) to produce one mole of carbon dioxide (CO2) and two moles of water (H2O).

2. Molar Mass:
Next, we need to calculate the molar mass of CO2. The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Since there are two oxygen atoms in one molecule of CO2, the molar mass of CO2 is calculated as follows:
Molar mass of CO2 = (2 × molar mass of O) + molar mass of C
= (2 × 16.00 g/mol) + 12.01 g/mol
= 32.00 g/mol + 12.01 g/mol
= 44.01 g/mol

3. Moles of CO2:
To determine the number of moles of CO2 produced, we divide the given mass of CO2 (22g) by its molar mass:
Moles of CO2 = Mass of CO2 / Molar mass of CO2
= 22g / 44.01 g/mol
= 0.5 mol

4. Stoichiometry:
According to the balanced chemical equation, one mole of ethane produces one mole of CO2. Therefore, the number of moles of ethane required can be determined as follows:
Moles of ethane = Moles of CO2
= 0.5 mol

5. Answer:
Hence, the number of moles of ethane required to produce 22g of CO2 after combustion is 0.5 mol.

1/2 moles