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 If a body is subjected to stresses in xy plane with stresses of 60N/mm² and 80N/mm² acting along x and y axes respectively. Also the shear stress acting is 10N/mm². Find the inclination of the plane in which shear stress is maximal.
  • a)
    45’
  • b)
    30’
  • c)
    60’
  • d)
    15’
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If a body is subjected to stresses in xy plane with stresses of 60N/mm...
Explanation: tan (2Ǿ)=2τ/[σ(x) – σ(y)].
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Most Upvoted Answer
If a body is subjected to stresses in xy plane with stresses of 60N/mm...
2 in the x-direction and 40N/mm2 in the y-direction, the resultant stress on the body can be calculated using the formula for resultant stress:

Resultant stress = sqrt((σx)^2 + (σy)^2 + 2τxy)

Where:
σx = stress in x-direction = 60N/mm2
σy = stress in y-direction = 40N/mm2
τxy = shear stress in xy plane (assumed to be zero in this case)

Plugging in the values:
Resultant stress = sqrt((60)^2 + (40)^2 + 2(0))
Resultant stress = sqrt(3600 + 1600)
Resultant stress = sqrt(5200)
Resultant stress ≈ 72.11 N/mm2

Therefore, the resultant stress on the body is approximately 72.11 N/mm2.
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If a body is subjected to stresses in xy plane with stresses of 60N/mm² and 80N/mm² acting along x and y axes respectively. Also the shear stress acting is 10N/mm². Find the inclination of the plane in which shear stress is maximal.a)45’b)30’c)60’d)15’Correct answer is option 'A'. Can you explain this answer?
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