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Which of the following complexes exhibits the highest paramagnetic behaviour ? [2008]       where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At.nosTi = 22, V = 23, Fe = 26, Co = 27)
  • a)
    [V(gly)2(OH)2(NH3)2]+
  • b)
    [Fe(en)(bpy)(NH3)2]2+
  • c)
    [Co(OX)2(OH)2]
  • d)
    [Ti(NH3)6]3+
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Which of the following complexes exhibits the highest paramagnetic beh...
More the number of unpaired electrons present in a complex more is its paramagnetic behaviour.
To find unpaired electrons let us calculate the oxidation states of elements in each complex and then write the electronic configuration for that oxidation state to find the number of unpaired electrons in it.
We find that in their complexes V, Fe, Co and Ti are in + 3, + 2, + 5, and + 3 oxidation states respectively. In these state the number of unpaired electrons present in them are 2, 4, 4 and 1 respectively. Since the maximum number of unpaired electrons are in cobalt complex so it has highest paramagnetic behaviour i.e. choice (c) is correct answer.
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Most Upvoted Answer
Which of the following complexes exhibits the highest paramagnetic beh...
To determine which complex exhibits the highest paramagnetic behavior, we need to analyze the oxidation states and number of unpaired electrons for each metal ion in the complexes.

a) [V(gly)2(OH)2(NH3)2]
The oxidation state of V is +5. It has 0 unpaired electrons.

b) [Fe(en)(bpy)(NH3)2]2
The oxidation state of Fe is +2. It has 4 unpaired electrons.

c) [Co(OX)2(OH)2]
The oxidation state of Co is +3. It has 1 unpaired electron.

Based on the number of unpaired electrons, the complex [Fe(en)(bpy)(NH3)2]2 exhibits the highest paramagnetic behavior with 4 unpaired electrons.
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Which of the following complexes exhibits the highest paramagnetic behaviour ? [2008] where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At.nosTi = 22, V = 23, Fe = 26, Co = 27)a)[V(gly)2(OH)2(NH3)2]+b)[Fe(en)(bpy)(NH3)2]2+c)[Co(OX)2(OH)2]–d)[Ti(NH3)6]3+Correct answer is option 'C'. Can you explain this answer?
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Which of the following complexes exhibits the highest paramagnetic behaviour ? [2008] where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At.nosTi = 22, V = 23, Fe = 26, Co = 27)a)[V(gly)2(OH)2(NH3)2]+b)[Fe(en)(bpy)(NH3)2]2+c)[Co(OX)2(OH)2]–d)[Ti(NH3)6]3+Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following complexes exhibits the highest paramagnetic behaviour ? [2008] where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At.nosTi = 22, V = 23, Fe = 26, Co = 27)a)[V(gly)2(OH)2(NH3)2]+b)[Fe(en)(bpy)(NH3)2]2+c)[Co(OX)2(OH)2]–d)[Ti(NH3)6]3+Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following complexes exhibits the highest paramagnetic behaviour ? [2008] where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At.nosTi = 22, V = 23, Fe = 26, Co = 27)a)[V(gly)2(OH)2(NH3)2]+b)[Fe(en)(bpy)(NH3)2]2+c)[Co(OX)2(OH)2]–d)[Ti(NH3)6]3+Correct answer is option 'C'. Can you explain this answer?.
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