Find the cube root of the 64 by prime factorision methord？？？？?

Question

Find the cube root of the 64  by prime factorision methord？？？？?

Answer

Answer

64=(2×2×2)(2×2×2)
↑ ↑
1st pair , 2nd pair
=2×2
=4

Answer

2√64
2√32
2√16
2√8
2√4
2√2
1

=√2×2×2×2×2×2
= 2×2
= 4

Answer

Answer

4 is the ans

Answer

Prime Factorization Method to Find Cube Root of 64

- Given number: 64
- We need to find the cube root of 64 using prime factorization method.

Step 1: Prime Factorization of 64
- Start by dividing the number 64 by the smallest prime number, which is 2.
- 64 ÷ 2 = 32
- Continue dividing by 2 until you cannot divide evenly anymore: 32 ÷ 2 = 16, 16 ÷ 2 = 8, 8 ÷ 2 = 4, 4 ÷ 2 = 2, 2 ÷ 2 = 1
- The prime factorization of 64 is 2 x 2 x 2 x 2 x 2 x 2 = 2^6

Step 2: Finding Cube Root
- To find the cube root, group the factors in sets of three.
- 64 = 2 x 2 x 2 x 2 x 2 x 2 = (2 x 2 x 2) x (2 x 2 x 2) = 2^3 x 2^3
- The cube root of 64 is the product of the cube roots of these groups, which is 2 x 2 = 4

Result: Cube Root of 64
- Cube root of 64 = 4

Therefore, the cube root of 64 is 4 when calculated using the prime factorization method.

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