Class 11 Exam > Class 11 Questions > A certain metal when irradiated to light (v=3...
Start Learning for Free
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz?
Most Upvoted Answer
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoe...
Community Answer
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoe...
Introduction:
When a metal is irradiated with light, it can emit photoelectrons. The kinetic energy of these photoelectrons depends on the frequency (v) of the incident light. In this scenario, we are given two different frequencies of light, and we need to determine the threshold frequency of the metal.
Threshold Frequency:
The threshold frequency (v0) is the minimum frequency of light required to remove an electron from the metal's surface. Below this frequency, no photoelectrons are emitted. The energy of a photon (E) can be calculated using the equation: E = hv, where h is the Planck's constant (6.626 x 10^-34 J.s).
Photoelectrons Comparison:
According to the given information, when the metal is irradiated with light of frequency v = 2.0 x 10^16 Hz, the photoelectrons have a certain kinetic energy (K1). When the metal is irradiated with light of frequency v = 3.2 x 10^16 Hz, the photoelectrons have twice the kinetic energy (2K1).
Explanation:
We can use the equation for the kinetic energy of a photoelectron to compare the two cases:
K1 = hv1 - φ (1)
2K1 = hv2 - φ (2)
where φ is the work function of the metal, representing the minimum energy required to remove an electron from its surface.
Calculations:
Substituting equation (1) into equation (2), we get:
hv2 - φ = 2(hv1 - φ)
hv2 - φ = 2hv1 - 2φ
Rearranging the equation, we have:
hv2 - 2hv1 = φ
Since we are interested in the threshold frequency (v0), we can set the kinetic energy of the photoelectron to zero:
0 = hv0 - φ
Simplifying the equation, we get:
hv0 = φ
Conclusion:
From the equation hv0 = φ, we can conclude that the threshold frequency (v0) is equal to the ratio of the work function (φ) to Planck's constant (h). Therefore, the threshold frequency of the metal is given by option (c) 1.2 x 10^16 Hz.
When a metal is irradiated with light, it can emit photoelectrons. The kinetic energy of these photoelectrons depends on the frequency (v) of the incident light. In this scenario, we are given two different frequencies of light, and we need to determine the threshold frequency of the metal.
Threshold Frequency:
The threshold frequency (v0) is the minimum frequency of light required to remove an electron from the metal's surface. Below this frequency, no photoelectrons are emitted. The energy of a photon (E) can be calculated using the equation: E = hv, where h is the Planck's constant (6.626 x 10^-34 J.s).
Photoelectrons Comparison:
According to the given information, when the metal is irradiated with light of frequency v = 2.0 x 10^16 Hz, the photoelectrons have a certain kinetic energy (K1). When the metal is irradiated with light of frequency v = 3.2 x 10^16 Hz, the photoelectrons have twice the kinetic energy (2K1).
Explanation:
We can use the equation for the kinetic energy of a photoelectron to compare the two cases:
K1 = hv1 - φ (1)
2K1 = hv2 - φ (2)
where φ is the work function of the metal, representing the minimum energy required to remove an electron from its surface.
Calculations:
Substituting equation (1) into equation (2), we get:
hv2 - φ = 2(hv1 - φ)
hv2 - φ = 2hv1 - 2φ
Rearranging the equation, we have:
hv2 - 2hv1 = φ
Since we are interested in the threshold frequency (v0), we can set the kinetic energy of the photoelectron to zero:
0 = hv0 - φ
Simplifying the equation, we get:
hv0 = φ
Conclusion:
From the equation hv0 = φ, we can conclude that the threshold frequency (v0) is equal to the ratio of the work function (φ) to Planck's constant (h). Therefore, the threshold frequency of the metal is given by option (c) 1.2 x 10^16 Hz.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz?
Question Description
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz?.
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz?.
Solutions for A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? defined & explained in the simplest way possible. Besides giving the explanation of
A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz?, a detailed solution for A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? has been provided alongside types of A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? theory, EduRev gives you an
ample number of questions to practice A certain metal when irradiated to light (v=3.2×10^16 Hz) emits photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light (v=2. 0×10^16 Hz) The threshold frequency of metal is (a)1.2×10^14 Hz (b)8×10^15 Hz (c)1.2×10^16 Hz (d)4×10^-12Hz? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup