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Y=(x^2-3x 3)(x^2 2x-1)?

Expanding the expression Y=(x^2-3x+3)(x^2+2x-1)

Step 1: Using FOIL method

FOIL method is used to multiply two binomials. It stands for First, Outer, Inner, Last. We can apply this method to multiply the two binomials in the expression Y.

First: Multiply the first terms of each binomial: x^2 * x^2 = x^4

Outer: Multiply the outer terms of each binomial: x^2 * 2x = 2x^3

Inner: Multiply the inner terms of each binomial: -3x * x^2 = -3x^3

Last: Multiply the last terms of each binomial: -3x * 2x = -6x^2

Now, add up all the products obtained in the above steps:

x^4 + 2x^3 - 3x^3 - 6x^2 + 3x^2 - 6x = x^4 - x^3 - 3x^2 - 6x

Step 2: Simplifying the expression

Now that we have expanded the expression using FOIL method, we can simplify it by combining like terms. Terms that have the same variables and exponents can be combined by adding or subtracting their coefficients.

The simplified expression becomes:

x^4 - x^3 - 3x^2 - 6x + (0 * 3) = x^4 - x^3 - 3x^2 - 6x

Therefore, the expanded expression Y=(x^2-3x+3)(x^2+2x-1) is equal to x^4 - x^3 - 3x^2 - 6x.

Answered by Infinity Academy · View profile

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