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A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution?
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A compound on analysis gave the following results C= 54.54%,H=9.09% an...
Given:
- C = 54.54%
- H = 9.09%
- Vapour density = 88
To find:
- Molecular formula of the compound
Solution:
1. Calculate the empirical formula of the compound:
- Assume 100g of the compound, then C = 54.54g and H = 9.09g
- Convert grams into moles by dividing by their respective atomic masses:
- C: 54.54 / 12.01 = 4.54 mol
- H: 9.09 / 1.01 = 9.0 mol
- Divide each mole value by the smallest value to get the mole ratio:
- C: 4.54 / 4.54 = 1
- H: 9.0 / 4.54 = 1.98
- Round off the mole ratio to the nearest whole number to get the empirical formula:
- C1H2
2. Calculate the molecular formula of the compound:
- Find the molecular weight of the empirical formula:
- C1H2 = 12.01 + (2 x 1.01) = 14.03 g/mol
- Divide the vapour density of the compound by the vapour density of hydrogen (which is 2) to get the relative molecular mass of the compound:
- Relative molecular mass = Vapour density / 2 = 88 / 2 = 44
- Divide the relative molecular mass by the empirical formula weight to get the whole number multiple:
- 44 / 14.03 = 3.13
- Round off the whole number multiple to the nearest whole number to get the molecular formula:
- C3H6
Answer: The molecular formula of the compound is C3H6.
- C = 54.54%
- H = 9.09%
- Vapour density = 88
To find:
- Molecular formula of the compound
Solution:
1. Calculate the empirical formula of the compound:
- Assume 100g of the compound, then C = 54.54g and H = 9.09g
- Convert grams into moles by dividing by their respective atomic masses:
- C: 54.54 / 12.01 = 4.54 mol
- H: 9.09 / 1.01 = 9.0 mol
- Divide each mole value by the smallest value to get the mole ratio:
- C: 4.54 / 4.54 = 1
- H: 9.0 / 4.54 = 1.98
- Round off the mole ratio to the nearest whole number to get the empirical formula:
- C1H2
2. Calculate the molecular formula of the compound:
- Find the molecular weight of the empirical formula:
- C1H2 = 12.01 + (2 x 1.01) = 14.03 g/mol
- Divide the vapour density of the compound by the vapour density of hydrogen (which is 2) to get the relative molecular mass of the compound:
- Relative molecular mass = Vapour density / 2 = 88 / 2 = 44
- Divide the relative molecular mass by the empirical formula weight to get the whole number multiple:
- 44 / 14.03 = 3.13
- Round off the whole number multiple to the nearest whole number to get the molecular formula:
- C3H6
Answer: The molecular formula of the compound is C3H6.
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A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution?
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A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution?.
A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound on analysis gave the following results C= 54.54%,H=9.09% and vapour density of the compound =88.determine the molecular formula of the compound? with solution?.
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