Suman has a piece of land which is in the shape of rhombus.She wants h...
Since perimeter of Rhombus = 400 m,each side = 100 m.Using Pythagoras theorem,AO^2 = 100^2 - 80^2 = 10000-6400 = 3600AO = 60SO AC = 2(AO) =120Area of Rhombus = 1/2 * Product of diagonals = 1/2 * 160 * 120 = 9600 m^2The area that each of the children get = 9600/2 = 4800 m^2
Suman has a piece of land which is in the shape of rhombus.She wants h...
Perimeter and Diagonal of Rhombus
The given rhombus has a perimeter of 400m. As the rhombus has four sides of equal length, each side is 400/4 = 100m. One of the diagonals has a length of 120m.
Area of Rhombus
The area of a rhombus can be calculated by multiplying the lengths of the two diagonals and dividing the result by two. Let's find the length of the other diagonal.
Using the Pythagorean Theorem, we can find the length of the other diagonal:
a² + b² = c²
100² + b² = 120²
b = sqrt(120² - 100²)
b = 80
So, the length of the other diagonal is 80m.
Now, we can calculate the area of the rhombus:
Area = (120 x 80) / 2
Area = 4800 square meters
Dividing the Rhombus
As the rhombus has been divided into two equal parts by drawing a diagonal, each part will have an area of half of the total area of the rhombus.
So, each son will get an area of:
Area of each part = 4800 / 2
Area of each part = 2400 square meters
Therefore, each son will get an area of 2400 square meters for their crops.
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