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A wire of uniform cross section and length Lead a resistance of 16 ohm. It is cut into four equal parts. Each part is streched uniformly to length L and all the four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed?
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A wire of uniform cross section and length Lead a resistance of 16 ohm. It is cut into four equal parts. Each part is streched uniformly to length L and all the four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed?
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A wire of uniform cross section and length Lead a resistance of 16 ohm. It is cut into four equal parts. Each part is streched uniformly to length L and all the four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A wire of uniform cross section and length Lead a resistance of 16 ohm. It is cut into four equal parts. Each part is streched uniformly to length L and all the four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire of uniform cross section and length Lead a resistance of 16 ohm. It is cut into four equal parts. Each part is streched uniformly to length L and all the four stretched parts are connected in parallel. Calculate the total resistance of the combination so formed?.
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