Class 11 Exam  >  Class 11 Questions  >  Can someone please help me with the numerical... Start Learning for Free
Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45?
Most Upvoted Answer
Can someone please help me with the numerical of chemistry part 1 text...
Community Answer
Can someone please help me with the numerical of chemistry part 1 text...
**Problem 2.10:**
The problem states: "If the velocity of the electron in Bohr's first orbit is 2.19 x 10^6 m/s, calculate the de Broglie wavelength associated with it."

To find the de Broglie wavelength associated with an electron in Bohr's first orbit, we can use the de Broglie equation:

λ = h / p

Where λ is the de Broglie wavelength, h is the Planck's constant (6.626 x 10^-34 J·s), and p is the momentum of the electron.

Step 1: Find the momentum of the electron.
The momentum of an electron can be calculated using the equation:

p = m * v

Where p is the momentum, m is the mass of the electron (9.11 x 10^-31 kg), and v is the velocity of the electron.

p = (9.11 x 10^-31 kg) * (2.19 x 10^6 m/s)
p ≈ 1.99 x 10^-24 kg·m/s

Step 2: Calculate the de Broglie wavelength.
Using the de Broglie equation:

λ = (6.626 x 10^-34 J·s) / (1.99 x 10^-24 kg·m/s)
λ ≈ 3.33 x 10^-10 m

Therefore, the de Broglie wavelength associated with the electron in Bohr's first orbit is approximately 3.33 x 10^-10 m.

**Problem 2.11:**
The problem states: "Calculate the wavelength of an electron moving with a velocity of 2.05 x 10^7 m/s."

To find the wavelength of an electron with a given velocity, we can use the de Broglie equation:

λ = h / p

Where λ is the de Broglie wavelength, h is the Planck's constant (6.626 x 10^-34 J·s), and p is the momentum of the electron.

Step 1: Find the momentum of the electron.
The momentum of an electron can be calculated using the equation:

p = m * v

Where p is the momentum, m is the mass of the electron (9.11 x 10^-31 kg), and v is the velocity of the electron.

p = (9.11 x 10^-31 kg) * (2.05 x 10^7 m/s)
p ≈ 1.87 x 10^-23 kg·m/s

Step 2: Calculate the de Broglie wavelength.
Using the de Broglie equation:

λ = (6.626 x 10^-34 J·s) / (1.87 x 10^-23 kg·m/s)
λ ≈ 3.54 x 10^-12 m

Therefore, the wavelength of the electron moving with a velocity of 2.05 x 10^7 m/s is approximately 3.54 x 10^-12 m.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
Explore Courses for Class 11 exam

Top Courses for Class 11

Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45?
Question Description
Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45?.
Solutions for Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? defined & explained in the simplest way possible. Besides giving the explanation of Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45?, a detailed solution for Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? has been provided alongside types of Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? theory, EduRev gives you an ample number of questions to practice Can someone please help me with the numerical of chemistry part 1 text of NCERT chapter -2 structure of atom problem 2.10 and 2.11 page - 45? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev