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A 200m long train crosses a women travelling at 9km/h in opposite direction in 7.2s then the velocity of the train is?
Most Upvoted Answer
A 200m long train crosses a women travelling at 9km/h in opposite dire...
Problem:

A 200m long train crosses a woman traveling at 9km/h in the opposite direction in 7.2s. Find the velocity of the train.

Solution:

Given:
- Length of the train (L) = 200m
- Velocity of the woman (v) = 9 km/h = 9000 m/3600 s = 2.5 m/s
- Time taken to cross the woman (t) = 7.2s

We need to find the velocity of the train (V).

Approach:
- When a train crosses a stationary object, the relative velocity of the train with respect to the object is equal to the sum of their individual velocities.
- In this case, the woman is stationary, so the velocity of the train with respect to the woman is the velocity of the train itself.
- We can use the formula: V = (L + S) / t, where S is the distance covered by the train relative to the woman.

Calculation:
- Distance covered by the train relative to the woman (S) = Length of the train + Distance travelled by the woman = L + (v * t)

Substituting the values:
S = 200m + (2.5m/s * 7.2s)
S = 200m + 18m
S = 218m

V = S / t
V = 218m / 7.2s
V ≈ 30.28 m/s

Therefore, the velocity of the train is approximately 30.28 m/s.

Conclusion:
The velocity of the train is approximately 30.28 m/s.
Community Answer
A 200m long train crosses a women travelling at 9km/h in opposite dire...
25.3m/sec may be I just tried
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A 200m long train crosses a women travelling at 9km/h in opposite direction in 7.2s then the velocity of the train is?
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