?48 sweet are to be distributed among three friends a ,b,c in such a w...
Distribution of sweets among three friends - A, B, and C
There are 48 sweets that need to be distributed among three friends - A, B, and C. The condition given is that B gets 5 sweets more than A. We need to find out how many sweets each friend will get.
Step 1: Set up equations
Let's assume that A gets x sweets. As B gets 5 sweets more than A, B will get (x+5) sweets. C will get the remaining sweets, which will be (48 - x - (x+5)). We can simplify this expression to (43 - 2x).
So, the equation for the distribution of sweets among the three friends will be:
x + (x+5) + (43 - 2x) = 48
Simplifying this equation, we get:
-x + 48 = 48
or
x = 0
Step 2: Interpretation of the equation
From the equation, we can see that A gets 0 sweets. This means that B gets 5 sweets and C gets 43 sweets.
Step 3: Final distribution of sweets
So, the final distribution of sweets among the three friends will be:
- A gets 0 sweets
- B gets 5 sweets
- C gets 43 sweets
Thus, we have successfully distributed the 48 sweets among three friends - A, B, and C, in such a way that B gets 5 sweets more than A.