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48 sweet are to be distributed among three friends a ,b,c in such a way b get 5 sweet more than a from an equation?
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?48 sweet are to be distributed among three friends a ,b,c in such a w...
Distribution of sweets among three friends - A, B, and C


There are 48 sweets that need to be distributed among three friends - A, B, and C. The condition given is that B gets 5 sweets more than A. We need to find out how many sweets each friend will get.


Step 1: Set up equations


Let's assume that A gets x sweets. As B gets 5 sweets more than A, B will get (x+5) sweets. C will get the remaining sweets, which will be (48 - x - (x+5)). We can simplify this expression to (43 - 2x).


So, the equation for the distribution of sweets among the three friends will be:


x + (x+5) + (43 - 2x) = 48


Simplifying this equation, we get:


-x + 48 = 48


or


x = 0


Step 2: Interpretation of the equation


From the equation, we can see that A gets 0 sweets. This means that B gets 5 sweets and C gets 43 sweets.


Step 3: Final distribution of sweets


So, the final distribution of sweets among the three friends will be:



  • A gets 0 sweets

  • B gets 5 sweets

  • C gets 43 sweets



Thus, we have successfully distributed the 48 sweets among three friends - A, B, and C, in such a way that B gets 5 sweets more than A.
Community Answer
?48 sweet are to be distributed among three friends a ,b,c in such a w...
Totle no of sweet=48 let a ,b, c sweet= x a,b,c 5b+a+c=48
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?48 sweet are to be distributed among three friends a ,b,c in such a way b get 5 sweet more than a from an equation?
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