Given:
The particle starts from rest and experiences constant acceleration for 20 seconds.
It covers a distance of S1 in the first 10 seconds and a distance of S2 in the next 10 seconds.

To Find:
We need to determine the relationship between S1 and S2.

Explanation:

Step 1: Understanding the Problem
The problem states that the particle starts from rest, which means its initial velocity (u) is zero. It also experiences constant acceleration, which implies that the acceleration (a) remains the same throughout the 20-second duration.

Step 2: Breaking Down the Problem
We can divide the problem into two parts:
1. The motion of the particle in the first 10 seconds.
2. The motion of the particle in the next 10 seconds.

Step 3: Analyzing the First 10 Seconds
During the first 10 seconds, the particle covers a distance of S1. We can use the kinematic equation to relate the distance, initial velocity, acceleration, and time:
S1 = u*t + (1/2)*a*t^2

Since the initial velocity (u) is zero, the equation simplifies to:
S1 = (1/2)*a*t^2 ... (Equation 1)

Step 4: Analyzing the Next 10 Seconds
During the next 10 seconds, the particle covers a distance of S2. The time for this motion is t = 10 seconds. Again, using the kinematic equation:
S2 = u*t + (1/2)*a*t^2

Since the initial velocity (u) is zero, the equation simplifies to:
S2 = (1/2)*a*t^2 ... (Equation 2)

Step 5: Analyzing the Relationship between S1 and S2
Comparing Equations 1 and 2, we observe that both equations have the same form:
S1 = (1/2)*a*t^2
S2 = (1/2)*a*t^2

This implies that the distances covered in the first and next 10 seconds are equal. Therefore, we can conclude that:
S1 = S2

Conclusion:
The distance covered by the particle in the first 10 seconds (S1) is equal to the distance covered in the next 10 seconds (S2). This relationship holds when the particle starts from rest and experiences constant acceleration for 20 seconds.

Please people look previous problem kam submitted answer please