Introduction:
In this scenario, we have two springs connected in a series combination and attached to a block of mass 'm' which is in equilibrium. We need to determine the force exerted by the spring on the block.

Analysis:
To solve this problem, we can consider the equilibrium condition of the block and the forces acting on it. The force exerted by each spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to its extension.

Hooke's Law:
Hooke's Law can be expressed as F = kx, where F is the force exerted by the spring, k is the spring constant, and x is the extension or compression of the spring from its equilibrium position.

Equilibrium Condition:
In equilibrium, the net force acting on the block is zero. Therefore, the force exerted by the springs must balance the weight of the block. We can write the equation as:

F1 + F2 = mg

where F1 and F2 are the forces exerted by the two springs, m is the mass of the block, and g is the acceleration due to gravity.

Calculating the Forces:
To calculate the forces exerted by the springs, we need to determine their extensions. The extension of a spring can be calculated by subtracting its equilibrium length from its stretched or compressed length.

Extension of Spring 1:
The extension of Spring 1 can be calculated as x1 = L1 - L0, where L1 is the stretched length of the spring and L0 is its equilibrium length. In this case, x1 = 5 cm - 3 cm = 2 cm.

Extension of Spring 2:
The extension of Spring 2 can be calculated as x2 = L2 - L0, where L2 is the stretched length of the spring and L0 is its equilibrium length. In this case, x2 = 4 cm - 3 cm = 1 cm.

Calculating the Spring Constants:
The spring constants can be calculated using the formula k = F/x, where k is the spring constant, F is the force exerted by the spring, and x is the extension or compression of the spring.

Spring Constant of Spring 1:
The spring constant of Spring 1 can be calculated as k1 = F1/x1. Since the extension is given as 2 cm, we convert it to meters by dividing by 100. Let's assume F1 as the force exerted by Spring 1.

Spring Constant of Spring 2:
Similarly, the spring constant of Spring 2 can be calculated as k2 = F2/x2. Since the extension is given as 1 cm, we convert it to meters by dividing by 100. Let's assume F2 as the force exerted by Spring 2.

Using Hooke's Law:
Now, we can use Hooke's Law to relate the forces exerted by the springs to their extensions.

F1 = k1 * x1
F2 = k2 * x2

Substituting the Values:
Substituting the known values, we have:
F1 = k1 * 2 cm
F2 = k2 *

Spring pull force (Kx)