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A solenoid has 10^3 turns per unit length. On passing a current of 2A, magnetic induction is measured to be 4πWb/m^2. Calculate magnetic susceptibility of core?
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A solenoid has 10^3 turns per unit length. On passing a current of 2A,...
**Calculation of Magnetic Susceptibility of Core**

**Given Data:**
- Number of turns per unit length of the solenoid (N) = 10^3 turns/m
- Current passing through the solenoid (I) = 2A
- Magnetic induction (B) = 4π Wb/m^2

**Formula:**
The magnetic field inside a solenoid is given by the equation:
B = μ₀ * μᵣ * N * I
where:
- B is the magnetic field in Tesla (T)
- μ₀ is the permeability of free space (4π * 10^-7 Tm/A)
- μᵣ is the relative permeability of the core material
- N is the number of turns per unit length of the solenoid
- I is the current passing through the solenoid

The relative permeability (μᵣ) of the core material is related to the magnetic susceptibility (χ) by the equation:
μᵣ = 1 + χ

**Calculation:**
1. Rearranging the equation B = μ₀ * μᵣ * N * I, we can solve for μᵣ:
μᵣ = B / (μ₀ * N * I)
= (4π Wb/m^2) / (4π * 10^-7 Tm/A * 10^3 turns/m * 2A)
= (4π / 4π) * (Wb/m^2 / Tm/A * turns/m * A)
= (Wb / T)
= T^-1

2. Substituting the value of μᵣ into the equation μᵣ = 1 + χ, we can solve for χ:
χ = μᵣ - 1
= (T^-1) - 1
= -1

**Answer:**
The magnetic susceptibility (χ) of the core is -1.
Community Answer
A solenoid has 10^3 turns per unit length. On passing a current of 2A,...
We know that,
B=u(H+M). & X=M/H
Given, B=4π Wbm^-2


Therefore,

4π=4π*10^-7 * (1+X)
10^7=1+X

Therefore, 10^7-1 = X
X~10^7
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A solenoid has 10^3 turns per unit length. On passing a current of 2A, magnetic induction is measured to be 4πWb/m^2. Calculate magnetic susceptibility of core?
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