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An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same?
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An object reaches a maximum height of 23.0m when thrown vertically upw...
Problem Statement
An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth? Assume that initial velocity is the same.
Solution
To solve this problem, we need to use the equations of motion. The first equation of motion is:
v = u + at
where,
v = final velocity
u = initial velocity
a = acceleration
t = time taken
v = final velocity
u = initial velocity
a = acceleration
t = time taken
The second equation of motion is:
s = ut + 1/2at^2
where,
s = distance traveled
u = initial velocity
a = acceleration
t = time taken
s = distance traveled
u = initial velocity
a = acceleration
t = time taken
Using these equations, we can find the time taken for the object to reach its maximum height on both the earth and the moon.
On Earth
Acceleration due to gravity on earth = g = 9.8 m/s^2
Initial velocity = u = 0 m/s
Maximum height = s = 23.0 m
Initial velocity = u = 0 m/s
Maximum height = s = 23.0 m
Using the second equation of motion, we can find the time taken for the object to reach its maximum height on earth:
s = ut + 1/2at^2
23 = 0t + 1/2(9.8)t^2
t = 2.42 seconds
23 = 0t + 1/2(9.8)t^2
t = 2.42 seconds
On Moon
Acceleration due to gravity on moon = g/6 = 9.8/6 = 1.63 m/s^2
Initial velocity = u = 0 m/s
Initial velocity = u = 0 m/s
Using the second equation of motion, we can find the distance traveled by the object on the moon:
s = ut + 1/2at^2
s = 0t + 1/2(1.63)t^2
s = 0.41t^2
s = 0t + 1/2(1.63)t^2
s = 0.41t^2
To find the maximum height on the moon, we need to find the time taken for the object to reach its maximum height:
v = u + at
0 = u + at
t = -u/a
0 = u + at
t = -u/a
Substituting the values of u and a, we get:
t = -0/1.63 = 0
This means that the object does not reach any maximum height on the moon as it falls back to the surface immediately.
Conclusion
The object does not reach any maximum height on the moon as the acceleration due to gravity is one sixth that on the earth. This means that the object falls back to the surface immediately.
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An object reaches a maximum height of 23.0m when thrown vertically upw...
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An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same?
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An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same?.
An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object reaches a maximum height of 23.0m when thrown vertically upward on the earth how high would it travel on the moon where the acceleration due to gravity is one sixth that on the earth ? Assume that initial velocity is the same?.
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