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Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]
- a)1s2 2s2 2p6 3s2
- b)1s2 2s2 2p6 3s1
- c)1s2 2s2 2p6 3s2 3p1
- d)1s2 2s2 2p6 3s2 3p2
Correct answer is option 'A'. Can you explain this answer?
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Of the given electronic configurations for the elements, which electro...
Mg = 1s2 22 2p6 3s2 After removing of 2 electron, the magnesium acquired noble gas configuration hence removing of 3rd electron will require large amount of energy.
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Of the given electronic configurations for the elements, which electro...
As the radius increase attraction decrease..
Thus, in first and second ionisation, enthalpy required would b comparatively less.. But to remove electron 3rd time from 2nd orbit it would require more energy.. So.. Ans a
Thus, in first and second ionisation, enthalpy required would b comparatively less.. But to remove electron 3rd time from 2nd orbit it would require more energy.. So.. Ans a
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Of the given electronic configurations for the elements, which electro...
Explanation:
The ionization energy is the energy required to remove an electron from an atom or ion. It is a measure of how tightly an electron is held by the nucleus. The second and third ionization energies refer to the energy required to remove the second and third electrons, respectively.
Electronic Configuration:
a) 1s2 2s2 2p6 3s2
b) 1s2 2s2 2p6 3s1
c) 1s2 2s2 2p6 3s2 3p1
d) 1s2 2s2 2p6 3s2 3p2
Explanation:
To understand why option A has an abnormally high difference in the second and third ionization energy, we need to analyze the electron configurations.
In option A: 1s2 2s2 2p6 3s2, there are two valence electrons in the 3s orbital. These electrons are relatively far from the nucleus and experience less effective nuclear charge. As a result, they are easier to remove compared to the core electrons.
When the first electron is removed, the resulting ion is 1s2 2s2 2p6 3s1. In this configuration, there is only one electron in the 3s orbital. This electron is now closer to the nucleus and experiences a stronger effective nuclear charge. Therefore, it is more difficult to remove compared to the initial two valence electrons.
The second ionization energy is the energy required to remove the second electron. In this case, the electron is being removed from the 3s orbital, which is now closer to the nucleus. As a result, the second ionization energy is higher compared to the first ionization energy.
When the second electron is removed, the resulting ion is 1s2 2s2 2p6. In this configuration, there are no more electrons in the 3s orbital. Therefore, the third ionization energy is significantly higher than the second ionization energy. The electron being removed is now a core electron, which is much closer to the nucleus and experiences a much stronger effective nuclear charge.
In options B, C, and D, the electron configurations do not have the same arrangement of electrons in the 3s orbital. This results in different ionization energies, but they do not exhibit an abnormally high difference between the second and third ionization energies.
Therefore, option A is the correct answer as it has an abnormally high difference in the second and third ionization energy due to the removal of electrons from the 3s orbital.
The ionization energy is the energy required to remove an electron from an atom or ion. It is a measure of how tightly an electron is held by the nucleus. The second and third ionization energies refer to the energy required to remove the second and third electrons, respectively.
Electronic Configuration:
a) 1s2 2s2 2p6 3s2
b) 1s2 2s2 2p6 3s1
c) 1s2 2s2 2p6 3s2 3p1
d) 1s2 2s2 2p6 3s2 3p2
Explanation:
To understand why option A has an abnormally high difference in the second and third ionization energy, we need to analyze the electron configurations.
In option A: 1s2 2s2 2p6 3s2, there are two valence electrons in the 3s orbital. These electrons are relatively far from the nucleus and experience less effective nuclear charge. As a result, they are easier to remove compared to the core electrons.
When the first electron is removed, the resulting ion is 1s2 2s2 2p6 3s1. In this configuration, there is only one electron in the 3s orbital. This electron is now closer to the nucleus and experiences a stronger effective nuclear charge. Therefore, it is more difficult to remove compared to the initial two valence electrons.
The second ionization energy is the energy required to remove the second electron. In this case, the electron is being removed from the 3s orbital, which is now closer to the nucleus. As a result, the second ionization energy is higher compared to the first ionization energy.
When the second electron is removed, the resulting ion is 1s2 2s2 2p6. In this configuration, there are no more electrons in the 3s orbital. Therefore, the third ionization energy is significantly higher than the second ionization energy. The electron being removed is now a core electron, which is much closer to the nucleus and experiences a much stronger effective nuclear charge.
In options B, C, and D, the electron configurations do not have the same arrangement of electrons in the 3s orbital. This results in different ionization energies, but they do not exhibit an abnormally high difference between the second and third ionization energies.
Therefore, option A is the correct answer as it has an abnormally high difference in the second and third ionization energy due to the removal of electrons from the 3s orbital.
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Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer?
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Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer?.
Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Of the given electronic configurations for the elements, which electronic configuration indicates that there will be abnormally high difference in the second and third ionization energy for the element? [1999]a)1s2 2s2 2p6 3s2 b)1s2 2s2 2p6 3s1c)1s2 2s2 2p6 3s2 3p1d)1s2 2s2 2p6 3s2 3p2 Correct answer is option 'A'. Can you explain this answer?.
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