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A 50 Hz, 13 kV three phase alternator with earthed neutral has a reactance of 8 ohms per phase and is connected to a bus bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral is 0.02 μF. The average rate of rise of re-striking voltage up to first peak is (in kv/μsec)
    Correct answer is between '0.2,0.4'. Can you explain this answer?
    Verified Answer
    A 50 Hz, 13 kV three phase alternator with earthed neutral has a react...
    Inductance per phase,

    Capacitance per phase, C = 0.02 μF
    Peak re-striking voltage,= 
    Frequency of oscillation, 
    = 7047.499 Hz
    Peak re-striking voltage occurs at a time given by

    Average rate of rise of re-striking voltage
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    A 50 Hz, 13 kV three phase alternator with earthed neutral has a react...
    Microfarads per phase. The length of the cable between the alternator and the circuit breaker is 500 meters and has a capacitance of 0.1 microfarads per kilometer between phase and neutral. Determine the charging current and the capacitance current through the circuit breaker when the alternator is connected to the bus bar.

    We can start by finding the total capacitance between phase and neutral up to the circuit breaker:

    C_total = C_cable + C_distributed
    C_total = 0.1 μF/km * 0.5 km + 0.02 μF/phase
    C_total = 0.07 μF/phase

    The charging current through the circuit breaker is given by:

    I_ch = 2πfVC_total
    I_ch = 2π*50*13,000*0.07*10^-6
    I_ch = 45.6 A

    The capacitance current through the circuit breaker is given by:

    I_cap = V/X_c
    X_c = (X_l^2 + X_c^2)^0.5
    X_l = 8 Ω
    X_c = 1/(2πfC_total)
    I_cap = 13,000/((8^2 + (1/(2π*50*0.07*10^-6))^2)^0.5)
    I_cap = 1.34 A

    Therefore, the charging current through the circuit breaker is 45.6 A and the capacitance current through the circuit breaker is 1.34 A when the alternator is connected to the bus bar.
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    Community Answer
    A 50 Hz, 13 kV three phase alternator with earthed neutral has a react...
    Inductance per phase,

    Capacitance per phase, C = 0.02 μF
    Peak re-striking voltage,= 
    Frequency of oscillation, 
    = 7047.499 Hz
    Peak re-striking voltage occurs at a time given by

    Average rate of rise of re-striking voltage
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    A 50 Hz, 13 kV three phase alternator with earthed neutral has a reactance of 8 ohms per phase and is connected to a bus bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral is 0.02 μF. The average rate of rise of re-striking voltage up to first peak is (in kv/μsec)Correct answer is between '0.2,0.4'. Can you explain this answer?
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    A 50 Hz, 13 kV three phase alternator with earthed neutral has a reactance of 8 ohms per phase and is connected to a bus bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral is 0.02 μF. The average rate of rise of re-striking voltage up to first peak is (in kv/μsec)Correct answer is between '0.2,0.4'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 Hz, 13 kV three phase alternator with earthed neutral has a reactance of 8 ohms per phase and is connected to a bus bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral is 0.02 μF. The average rate of rise of re-striking voltage up to first peak is (in kv/μsec)Correct answer is between '0.2,0.4'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 Hz, 13 kV three phase alternator with earthed neutral has a reactance of 8 ohms per phase and is connected to a bus bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral is 0.02 μF. The average rate of rise of re-striking voltage up to first peak is (in kv/μsec)Correct answer is between '0.2,0.4'. Can you explain this answer?.
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