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Tunnel is dug along a chord of earth at a perpendicular distance R/2 from the Earths centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel then draw the graphs between the pressing force by the particle on the wall with x and the acceleration of the particle varies with the x (distance of the particle from the centre)?
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Tunnel is dug along a chord of earth at a perpendicular distance R/2 f...
Let d be the distance from centre of earth to man ‘m’ then

M be the mass of the earth, M' the mass of the sphere of radius d/2.Read more on Sarthaks.com - https://www.sarthaks.com/42923/tunnel-is-dug-along-chord-of-the-earth-at-a-perpendicular-distance-r-from-the-earths-centre.



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Tunnel is dug along a chord of earth at a perpendicular distance R/2 f...
Introduction:
The problem states that a tunnel is dug along a chord of the Earth, at a perpendicular distance of R/2 from the Earth's center. The tunnel's wall is assumed to be frictionless. A particle is released from one end of the tunnel, and we need to draw graphs between the pressing force by the particle on the wall with x and the acceleration of the particle as it varies with x.

Explanation:
To understand the problem, let's break it down into steps and analyze each step in detail.

Step 1: Understanding the Setup
- The tunnel is dug along a chord of the Earth, which means it is a straight line connecting two points on the Earth's surface.
- The perpendicular distance of the tunnel from the Earth's center is R/2. This means that the tunnel is not at the Earth's equator but at a latitude where the distance from the center is R/2.
- The wall of the tunnel is assumed to be frictionless, which means there is no friction force acting on the particle as it moves along the tunnel.

Step 2: Analyzing the Particle's Motion
- When the particle is released from one end of the tunnel, it will start moving towards the other end.
- As the particle moves along the tunnel, its distance from the Earth's center will change, which we denote as x.
- The particle experiences a gravitational force towards the Earth's center, which is given by the equation F = (G * M * m) / r^2, where G is the gravitational constant, M is the mass of the Earth, m is the mass of the particle, and r is the distance between the particle and the Earth's center.

Step 3: Graphing the Pressing Force with x
- The pressing force by the particle on the wall of the tunnel can be calculated using the equation F_press = F * cos(theta), where F is the gravitational force and theta is the angle between the gravitational force and the tunnel's wall.
- Since the tunnel is perpendicular to the radius of the Earth at the point where the particle is located, the angle theta is 90 degrees. Therefore, cos(theta) = 0, and the pressing force is zero. As a result, the graph of pressing force vs. x will be a straight line at zero.

Step 4: Graphing the Acceleration with x
- The acceleration of the particle can be calculated using the equation a = F_net / m, where F_net is the net force acting on the particle.
- The net force acting on the particle is the gravitational force minus the pressing force, as there are no other forces acting on the particle.
- Since the pressing force is zero, the net force acting on the particle is equal to the gravitational force.
- Therefore, the acceleration of the particle is constant and equal to the gravitational acceleration, g = (G * M) / r^2.
- As the distance x from the Earth's center increases, the acceleration remains constant.
- Thus, the graph of acceleration vs. x will be a horizontal line at a constant value.

Conclusion:
In conclusion, the graph of pressing force by the particle on the wall of the tunnel vs. x will be a straight line at zero, as the pressing force is zero. The graph of acceleration of the
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Tunnel is dug along a chord of earth at a perpendicular distance R/2 from the Earths centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel then draw the graphs between the pressing force by the particle on the wall with x and the acceleration of the particle varies with the x (distance of the particle from the centre)?
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Tunnel is dug along a chord of earth at a perpendicular distance R/2 from the Earths centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel then draw the graphs between the pressing force by the particle on the wall with x and the acceleration of the particle varies with the x (distance of the particle from the centre)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Tunnel is dug along a chord of earth at a perpendicular distance R/2 from the Earths centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel then draw the graphs between the pressing force by the particle on the wall with x and the acceleration of the particle varies with the x (distance of the particle from the centre)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Tunnel is dug along a chord of earth at a perpendicular distance R/2 from the Earths centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel then draw the graphs between the pressing force by the particle on the wall with x and the acceleration of the particle varies with the x (distance of the particle from the centre)?.
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