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The solubility product of AgI at 25ºC is 1.0 × 10–16 mol2 L–2. The solubiliy of AgI in  10–4 N solution of KI at 25ºC is approximately(in mol L–1) [2003]
  • a)
    1.0 × 10–8
  • b)
    1.0 × 10–16
  • c)
    1.0 × 10–12
  • d)
    1.0 × 10–10
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The solubility product of AgI at 25ºC is 1.0 × 10–16 ...
Ksp for AgI = 1 × 10–16 In solution of KI, I would be due to the both AgI and KI, 10–4 solution KI would provide = 10–4 I
AgI would provide, say = x I (x is solubility of AgI)
as x is very small ∴ x2 can be ignored
∴      10–4 x = 10–16
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The solubility product of AgI at 25ºC is 1.0 × 10–16 mol2 L–2. The solubiliy of AgI in 10–4 N solution of KI at 25ºC is approximately(in mol L–1) [2003]a)1.0 × 10–8b)1.0 × 10–16c)1.0 × 10–12d)1.0 × 10–10Correct answer is option 'C'. Can you explain this answer?
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The solubility product of AgI at 25ºC is 1.0 × 10–16 mol2 L–2. The solubiliy of AgI in 10–4 N solution of KI at 25ºC is approximately(in mol L–1) [2003]a)1.0 × 10–8b)1.0 × 10–16c)1.0 × 10–12d)1.0 × 10–10Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The solubility product of AgI at 25ºC is 1.0 × 10–16 mol2 L–2. The solubiliy of AgI in 10–4 N solution of KI at 25ºC is approximately(in mol L–1) [2003]a)1.0 × 10–8b)1.0 × 10–16c)1.0 × 10–12d)1.0 × 10–10Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The solubility product of AgI at 25ºC is 1.0 × 10–16 mol2 L–2. The solubiliy of AgI in 10–4 N solution of KI at 25ºC is approximately(in mol L–1) [2003]a)1.0 × 10–8b)1.0 × 10–16c)1.0 × 10–12d)1.0 × 10–10Correct answer is option 'C'. Can you explain this answer?.
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