Class 11 Exam  >  Class 11 Questions  >  It takes 26 s for 10 mL of H2 gas to effuse t... Start Learning for Free
It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) is
  • a)
    40
  • b)
    50
  • c)
    80
  • d)
    100
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane,...
View all questions of this test
Most Upvoted Answer
It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane,...
**Explanation:**

To solve this problem, we can use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, the equation can be written as:

Rate1/Rate2 = sqrt(Molar Mass2/Molar Mass1)

Given:
Rate1 = 10 mL / 26 s
Rate2 = 10 mL / 130 s

Let's calculate the molar mass of the unknown gas using Graham's law of effusion:

Rate1/Rate2 = sqrt(Molar Mass2/Molar Mass1)

(10 mL / 26 s) / (10 mL / 130 s) = sqrt(Molar Mass2/Molar Mass1)

Simplifying the equation:

(130 s / 26 s) = sqrt(Molar Mass2/Molar Mass1)

5 = sqrt(Molar Mass2/Molar Mass1)

Squaring both sides of the equation:

25 = Molar Mass2/Molar Mass1

Since we know that the molar mass of hydrogen gas (H2) is 2 g/mol, we can substitute the values into the equation:

25 = Molar Mass2/2

Molar Mass2 = 2 * 25

Molar Mass2 = 50 g/mol

Therefore, the molar mass of the unknown gas is 50 g/mol, which corresponds to option B.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
Explore Courses for Class 11 exam

Similar Class 11 Doubts

Top Courses for Class 11

It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer?
Question Description
It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer?.
Solutions for It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer?, a detailed solution for It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice It takes 26 s for 10 mL of H2 gas to effuse through a porous membrane, it takes 130 s for 10 mL of an unknown gas under identical conditions to effuse. Hence, molar mass of the unknown gas (in g mol-1) isa)40b)50c)80d)100Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev