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A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?
- a)2
- b)3
- c)4
- d)5
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0...
Answer should be (B) As according to question .. truth table will be like
A B C D f
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
0 0 1 1 0
0 1 0 0 0
0 1 0 1 1
0 1 1 0 1
0 1 1 1 1
1 0 0 0 1
1 0 0 1 1
1 0 1 0 dont care
1 0 1 1 dont care
1 1 0 0 dont care
1 1 0 1 dont care
1 1 1 0 dont care
1 1 1 1 dont care
using this truth table we get 3 sub cube which are combined with following minterms A (8,9,10,11,12,13,14,15) , BD( 5,13,7,15) and BC(6,7,14,15)
SO f = A+ BD +BC= A+ B(C+D)
SO minimum gate required 2 OR gate and 1 AND gate = 3 minimum gate ...
A B C D f
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
0 0 1 1 0
0 1 0 0 0
0 1 0 1 1
0 1 1 0 1
0 1 1 1 1
1 0 0 0 1
1 0 0 1 1
1 0 1 0 dont care
1 0 1 1 dont care
1 1 0 0 dont care
1 1 0 1 dont care
1 1 1 0 dont care
1 1 1 1 dont care
using this truth table we get 3 sub cube which are combined with following minterms A (8,9,10,11,12,13,14,15) , BD( 5,13,7,15) and BC(6,7,14,15)
SO f = A+ BD +BC= A+ B(C+D)
SO minimum gate required 2 OR gate and 1 AND gate = 3 minimum gate ...
Most Upvoted Answer
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0...
Explanation:
Using Logic Gates:
- We can use AND, OR, and NOT gates to design the combinational circuit.
- The input consists of 4 bits representing the digits 0 to 9.
- We need to design a circuit that outputs 1 if the input represents the digit 5, and 0 otherwise.
Designing the Circuit:
- We need to check if the input is '0101' to identify the digit 5.
- We can use AND gates to check each individual bit of the input.
- Then, we can use OR gates to combine the results of the AND gates.
- Finally, we use a single gate to output the final result.
Minimum Number of Gates:
- One AND gate is needed for each bit of the input (4 AND gates).
- One OR gate is needed to combine the results of the AND gates.
- One NOT gate may be needed to invert the final result (if required).
- Therefore, the minimum number of gates required is 3 (4 AND gates + 1 OR gate).
Conclusion:
- The minimum number of gates required to design the combinational circuit that outputs 1 if the input represents the digit 5 is 3.
Using Logic Gates:
- We can use AND, OR, and NOT gates to design the combinational circuit.
- The input consists of 4 bits representing the digits 0 to 9.
- We need to design a circuit that outputs 1 if the input represents the digit 5, and 0 otherwise.
Designing the Circuit:
- We need to check if the input is '0101' to identify the digit 5.
- We can use AND gates to check each individual bit of the input.
- Then, we can use OR gates to combine the results of the AND gates.
- Finally, we use a single gate to output the final result.
Minimum Number of Gates:
- One AND gate is needed for each bit of the input (4 AND gates).
- One OR gate is needed to combine the results of the AND gates.
- One NOT gate may be needed to invert the final result (if required).
- Therefore, the minimum number of gates required is 3 (4 AND gates + 1 OR gate).
Conclusion:
- The minimum number of gates required to design the combinational circuit that outputs 1 if the input represents the digit 5 is 3.
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A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?
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A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
Solutions for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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