Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > A circuit outputs a digit in the form of 4 bi...
Start Learning for Free
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?
- a)2
- b)3
- c)4
- d)5
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0...
Answer should be (B) As according to question .. truth table will be like
A B C D f
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
0 0 1 1 0
0 1 0 0 0
0 1 0 1 1
0 1 1 0 1
0 1 1 1 1
1 0 0 0 1
1 0 0 1 1
1 0 1 0 dont care
1 0 1 1 dont care
1 1 0 0 dont care
1 1 0 1 dont care
1 1 1 0 dont care
1 1 1 1 dont care
using this truth table we get 3 sub cube which are combined with following minterms A (8,9,10,11,12,13,14,15) , BD( 5,13,7,15) and BC(6,7,14,15)
SO f = A+ BD +BC= A+ B(C+D)
SO minimum gate required 2 OR gate and 1 AND gate = 3 minimum gate ...
A B C D f
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
0 0 1 1 0
0 1 0 0 0
0 1 0 1 1
0 1 1 0 1
0 1 1 1 1
1 0 0 0 1
1 0 0 1 1
1 0 1 0 dont care
1 0 1 1 dont care
1 1 0 0 dont care
1 1 0 1 dont care
1 1 1 0 dont care
1 1 1 1 dont care
using this truth table we get 3 sub cube which are combined with following minterms A (8,9,10,11,12,13,14,15) , BD( 5,13,7,15) and BC(6,7,14,15)
SO f = A+ BD +BC= A+ B(C+D)
SO minimum gate required 2 OR gate and 1 AND gate = 3 minimum gate ...
Most Upvoted Answer
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0...
Explanation:
Using Logic Gates:
- We can use AND, OR, and NOT gates to design the combinational circuit.
- The input consists of 4 bits representing the digits 0 to 9.
- We need to design a circuit that outputs 1 if the input represents the digit 5, and 0 otherwise.
Designing the Circuit:
- We need to check if the input is '0101' to identify the digit 5.
- We can use AND gates to check each individual bit of the input.
- Then, we can use OR gates to combine the results of the AND gates.
- Finally, we use a single gate to output the final result.
Minimum Number of Gates:
- One AND gate is needed for each bit of the input (4 AND gates).
- One OR gate is needed to combine the results of the AND gates.
- One NOT gate may be needed to invert the final result (if required).
- Therefore, the minimum number of gates required is 3 (4 AND gates + 1 OR gate).
Conclusion:
- The minimum number of gates required to design the combinational circuit that outputs 1 if the input represents the digit 5 is 3.
Using Logic Gates:
- We can use AND, OR, and NOT gates to design the combinational circuit.
- The input consists of 4 bits representing the digits 0 to 9.
- We need to design a circuit that outputs 1 if the input represents the digit 5, and 0 otherwise.
Designing the Circuit:
- We need to check if the input is '0101' to identify the digit 5.
- We can use AND gates to check each individual bit of the input.
- Then, we can use OR gates to combine the results of the AND gates.
- Finally, we use a single gate to output the final result.
Minimum Number of Gates:
- One AND gate is needed for each bit of the input (4 AND gates).
- One OR gate is needed to combine the results of the AND gates.
- One NOT gate may be needed to invert the final result (if required).
- Therefore, the minimum number of gates required is 3 (4 AND gates + 1 OR gate).
Conclusion:
- The minimum number of gates required to design the combinational circuit that outputs 1 if the input represents the digit 5 is 3.
Attention Computer Science Engineering (CSE) Students!
To make sure you are not studying endlessly, EduRev has designed Computer Science Engineering (CSE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Computer Science Engineering (CSE).
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Similar Computer Science Engineering (CSE) Doubts
Top Courses for Computer Science Engineering (CSE)View all
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?
Question Description
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
Solutions for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A circuit outputs a digit in the form of 4 bits. 0 is represented by 0000, 1 by 0001, …, 9 by 1001. A combinational circuit is to be designed which takes these 4 bits as input and outputs 1 if the digit > 5, and 0 otherwise. If only AND, OR and NOT gates may be used, what is the minimum number of gates required?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
|
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup