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A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.
- a)5.88N/mm²
- b)2.28N/mm²
- c)4.56N/mm²
- d)3.66N/mm²
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A high pressure cylinder consists of a steel tube with inner and outer...
Explanation: σ=P[D₃²+D₂²]/[D₃²-D₂²] where D₂=40mm and D₃=60mm.
Most Upvoted Answer
A high pressure cylinder consists of a steel tube with inner and outer...
To determine the maximum principal stress induced in the high pressure cylinder, we need to use the formula for the maximum principal stress in a thick-walled cylinder:
σ_max = (P * (r_i^2 + r_i * r_o + r_o^2)) / (r_i^2 - r_i * r_o + r_o^2)
Where:
σ_max is the maximum principal stress
P is the applied pressure
r_i is the inner radius of the high pressure cylinder
r_o is the outer radius of the high pressure cylinder
In this case, the inner and outer diameters of the high pressure cylinder are given as 30mm and 60mm respectively. We can use these values to calculate the inner and outer radii:
r_i = 15mm
r_o = 30mm
The outer diameter of the jacketing tube is given as 90mm, so the outer radius of the jacketing tube is:
r_j = 45mm
Now we can substitute the values into the formula to calculate the maximum principal stress:
σ_max = (P * (15^2 + 15 * 30 + 30^2)) / (15^2 - 15 * 30 + 30^2)
Since the value for the applied pressure (P) is not provided in the question, we cannot determine the value of the maximum principal stress without this information.
σ_max = (P * (r_i^2 + r_i * r_o + r_o^2)) / (r_i^2 - r_i * r_o + r_o^2)
Where:
σ_max is the maximum principal stress
P is the applied pressure
r_i is the inner radius of the high pressure cylinder
r_o is the outer radius of the high pressure cylinder
In this case, the inner and outer diameters of the high pressure cylinder are given as 30mm and 60mm respectively. We can use these values to calculate the inner and outer radii:
r_i = 15mm
r_o = 30mm
The outer diameter of the jacketing tube is given as 90mm, so the outer radius of the jacketing tube is:
r_j = 45mm
Now we can substitute the values into the formula to calculate the maximum principal stress:
σ_max = (P * (15^2 + 15 * 30 + 30^2)) / (15^2 - 15 * 30 + 30^2)
Since the value for the applied pressure (P) is not provided in the question, we cannot determine the value of the maximum principal stress without this information.
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A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer?
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A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer?.
A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A high pressure cylinder consists of a steel tube with inner and outer diameters 30 and 60mm respectively. It is jacketed by an outer steel tube, having an outer diameter of 90mm. Maximum principal stress induced is 80N/mm². Calculate the shrinkage pressure.a)5.88N/mm²b)2.28N/mm²c)4.56N/mm²d)3.66N/mm²Correct answer is option 'B'. Can you explain this answer?.
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