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The piston rod of a hydraulic cylinder exerts an operating force of 10kN. The allowable stress in the cylinder is 70N/mm². Calculate the thickness of the cylinder using Clavarinoe’s equation. Diameter of the cylinder is 240mm.μ=0.3 and pressure in cylinder is 15MPa.
  • a)
    35mm
  • b)
    30mm
  • c)
    27mm
  • d)
    None of the listed
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The piston rod of a hydraulic cylinder exerts an operating force of 10...
Explanation: t=D/2[√[σ+(1-2μ) P /σ-(1+μ)P] -1 ].
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Most Upvoted Answer
The piston rod of a hydraulic cylinder exerts an operating force of 10...
To determine the maximum allowable cross-sectional area of the piston rod, we can use the formula for stress:

Stress = Force / Area

Given that the operating force is 10 kN and the allowable stress is 70 N/mm^2, we can rearrange the formula to solve for the cross-sectional area:

Area = Force / Stress

Area = 10,000 N / 70 N/mm^2

Area = 142.86 mm^2

Therefore, the maximum allowable cross-sectional area of the piston rod is 142.86 mm^2.
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The piston rod of a hydraulic cylinder exerts an operating force of 10kN. The allowable stress in the cylinder is 70N/mm². Calculate the thickness of the cylinder using Clavarinoe’s equation. Diameter of the cylinder is 240mm.μ=0.3 and pressure in cylinder is 15MPa.a)35mmb)30mmc)27mmd)None of the listedCorrect answer is option 'C'. Can you explain this answer?
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