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Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r – 1). Let Tr = V r + 1 – Vr – 2 and Qr = Tr + 1 – Tr for r = 1, 2,.....
Tr is always
  • a)
    an odd number
  • b)
    an even number
  • c)
    a prime number
  • d)
    a composite number
Correct answer is option 'D'. Can you explain this answer?
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Let Vr denote the sum of first r terms of an arithmetic progression (A...
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Let Vr denote the sum of first r terms of an arithmetic progression (A...
We have the first term of the A.P. as r and the common difference as (2r - 1).
Thus, the second term would be:
r + (2r - 1) = 3r - 1
The third term would be:
r + 2(2r - 1) = 5r - 3
The fourth term would be:
r + 3(2r - 1) = 7r - 5
And so on.
Thus, the sum of the first r terms of this A.P. would be:
Vr = r + (3r - 1) + (5r - 3) + (7r - 5) + ... + (2r(r-1) - (2r - 3))
We can simplify this expression by grouping the terms as follows:
Vr = (r + (3r - 1) + (5r - 3) + (7r - 5) + ... + (2r(r-1) - (2r - 3))) + (-1 - 2 - 3 - 4 - ... - (r - 2))
The first part of this expression is simply the sum of the first r terms of an A.P. with first term r and common difference (2r - 1). We can use the formula for the sum of an A.P. to simplify this part:
Vr = (r/2)(2r + (r - 1)(2r - 1)) + (-1 - 2 - 3 - 4 - ... - (r - 2))
Simplifying the first part further, we get:
Vr = r(3r - 1) + (-1 - 2 - 3 - 4 - ... - (r - 2))
Now, we can use the formula for the sum of the first n natural numbers to simplify the second part:
Vr = r(3r - 1) - [(r - 2)(r - 1)/2]
Expanding and simplifying the second part, we get:
Vr = r(3r - 1) - (r^2 - 3r + 2)/2
Vr = (7r^2 - 7r + 2)/2
Thus, the sum of the first r terms of the given A.P. is (7r^2 - 7r + 2)/2.
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Let Vr denote the sum of first r terms of an arithmetic progression (A...
Correct answer is option.D)a composite number
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Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r – 1). Let Tr = V r + 1 – Vr – 2 and Qr = Tr + 1 – Tr for r = 1, 2,.....Tr is alwaysa)an odd numberb)an even numberc)a prime numberd)a composite numberCorrect answer is option 'D'. Can you explain this answer?
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Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r – 1). Let Tr = V r + 1 – Vr – 2 and Qr = Tr + 1 – Tr for r = 1, 2,.....Tr is alwaysa)an odd numberb)an even numberc)a prime numberd)a composite numberCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r – 1). Let Tr = V r + 1 – Vr – 2 and Qr = Tr + 1 – Tr for r = 1, 2,.....Tr is alwaysa)an odd numberb)an even numberc)a prime numberd)a composite numberCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let Vr denote the sum of first r terms of an arithmetic progression (A.P.) whose first term is r and the common difference is (2r – 1). Let Tr = V r + 1 – Vr – 2 and Qr = Tr + 1 – Tr for r = 1, 2,.....Tr is alwaysa)an odd numberb)an even numberc)a prime numberd)a composite numberCorrect answer is option 'D'. Can you explain this answer?.
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