Prove that tanA/1+cotA. + CotA/1-tanA = 1+secAcosecA
Proof:
Given:
tanA/1+cotA + cotA/1-tanA = 1+secA cosecA
Proof:
Step 1: Simplifying LHS
tanA/1+cotA + cotA/1-tanA
= (tanA * cotA + cotA * 1) / (1 + cotA) (Finding a common denominator)
= (sinA/cosA * cosA/sinA + cosA/sinA) / (1 + cosA/sinA) (Applying trigonometric identities)
= (1 + cosA) / sinA (Simplifying)
Step 2: Simplifying RHS
1+secA cosecA
= 1 + (1/cosA) * (1/sinA) (Using trigonometric identities)
= 1 + (sinA * cosA) / (cosA * sinA) (Finding a common denominator)
= 1 + 1 (Simplifying)
= 2
Step 3: Comparing LHS and RHS
We have simplified LHS to (1 + cosA) / sinA and RHS to 2.
Since (1 + cosA) / sinA is not equal to 2, the given equation is incorrect.
Therefore, tanA/1+cotA + cotA/1-tanA is not equal to 1+secA cosecA.
Prove that tanA/1+cotA. + CotA/1-tanA = 1+secAcosecA
Hey just convert it into the term of sin in tan and cos and then solve