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Three distinct numbers are selected from first hundred natural numbers. The probability that all the three numbers are divisible by 2 and 3 is
[JEE 2004]
  • a)
    4/25
  • b)
    4/35
  • c)
    4/55
  • d)
    4/1155
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Three distinct numbers are selected from first hundred natural numbers...
If a number is to be divisible by both 2 and 3, it should be divisible by their L.C.M., L.C.M of 2 and 3 is 6. The numbers are 6, 12, 18, ....., 96. The total number is 16.
Hence, the probability is :
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Three distinct numbers are selected from first hundred natural numbers. The probability that all the three numbers are divisible by 2 and 3 is[JEE 2004]a)4/25b)4/35c)4/55d)4/1155Correct answer is option 'D'. Can you explain this answer?
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