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For a colony of 10000 persons having sewage flow rate 250 lpcd with a BOD of 320 mg/l and organic loading of 200 Kg/day/ha, the area of the oxidation pond required for treating the sewage of the colony is _______
  • a)
    3.6 hectares
  • b)
    4 hectares
  • c)
    4.6 hectored
  • d)
    2 hectare
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For a colony of 10000 persons having sewage flow rate 250 lpcd with a ...
Total BOD produced per day = 
Organic loading rate = 200 kg/day/ha
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For a colony of 10000 persons having sewage flow rate 250 lpcd with a ...
Calculation of Oxidation Pond Area for a Colony

Given data:
Population of Colony (N) = 10000
Sewage flow rate (Q) = 250 lpcd (liters per capita per day)
BOD of sewage = 320 mg/l
Organic loading (OL) = 200 Kg/day/ha

We can calculate the total sewage generated by the colony as follows:
Total sewage generated = N x Q
= 10000 x 250
= 2500000 liters per day

Calculation of Organic Load:
Organic load = Total sewage generated x BOD
= 2500000 x 320 / 1000
= 800000 Kg/day

Calculation of Oxidation Pond Area:
We know that the organic loading of the oxidation pond should be in the range of 50 to 100 Kg/day/ha. Therefore, the area of the oxidation pond required can be calculated as follows:
Required area of the oxidation pond = Organic load / Organic loading per hectare
= 800000 / 200
= 4000 hectares

Hence, the area of the oxidation pond required for treating the sewage of the colony is 4 hectares.
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For a colony of 10000 persons having sewage flow rate 250 lpcd with a BODof 320 mg/l and organic loading of 200 Kg/day/ha, the area of the oxidation pond required for treating the sewage of the colony is _______a)3.6 hectaresb)4 hectaresc)4.6 hectoredd)2 hectareCorrect answer is option 'B'. Can you explain this answer?
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For a colony of 10000 persons having sewage flow rate 250 lpcd with a BODof 320 mg/l and organic loading of 200 Kg/day/ha, the area of the oxidation pond required for treating the sewage of the colony is _______a)3.6 hectaresb)4 hectaresc)4.6 hectoredd)2 hectareCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about For a colony of 10000 persons having sewage flow rate 250 lpcd with a BODof 320 mg/l and organic loading of 200 Kg/day/ha, the area of the oxidation pond required for treating the sewage of the colony is _______a)3.6 hectaresb)4 hectaresc)4.6 hectoredd)2 hectareCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a colony of 10000 persons having sewage flow rate 250 lpcd with a BODof 320 mg/l and organic loading of 200 Kg/day/ha, the area of the oxidation pond required for treating the sewage of the colony is _______a)3.6 hectaresb)4 hectaresc)4.6 hectoredd)2 hectareCorrect answer is option 'B'. Can you explain this answer?.
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