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A wet porous substance in open air loses its moisture at a rate proportional to the moisture content.If a sheet hang in the wind loses half its moisture during first hour and after t hours will have lost 99% then value of (2^(t/2))
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A wet porous substance in open air loses its moisture at a rate propor...
From the given information it is clear that the half life of this reaction is 1 hour. Also, according to chemical kinetics a first order reaction (like this one) the full life of the reaction is when 99% of the reactants gets consumed (since theoretically a first order never goes to completion as it being an exponential function) 

full life = 2 x half life
t = 2 hours 
So, 2^(2/2) = 2
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A wet porous substance in open air loses its moisture at a rate proportional to the moisture content.If a sheet hang in the wind loses half its moisture during first hour and after t hours will have lost 99% then value of (2^(t/2))
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