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In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]
- a)15.45
- b)16.45
- c)17.45
- d)14.45
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In Duma's method of estimation of nitrogen 0.35 g of an organic co...
Given wt of compound taken (w) = 0.35 g
Volume of nitrogen collected (V) = 55 ml
Room temperature (t K) = 300 K
Atmospheric pressure (P) = 715 mm Aq. tension (ρ) = 15 mm
Calculation -Volume of N2 at NTP
Volume of nitrogen collected (V) = 55 ml
Room temperature (t K) = 300 K
Atmospheric pressure (P) = 715 mm Aq. tension (ρ) = 15 mm
Calculation -Volume of N2 at NTP
% of nitrogen
Most Upvoted Answer
In Duma's method of estimation of nitrogen 0.35 g of an organic co...
Given Data:
- Mass of organic compound = 0.35 g
- Volume of nitrogen collected = 55 mL
- Temperature = 300 K
- Pressure = 715 mm
- Aqueous tension at 300 K = 15 mm
Calculations:
1. Convert the volume of nitrogen collected to liters:
Volume of nitrogen = 55 mL = 0.055 L
2. Convert the pressure to atm:
Pressure = 715 mm = 715/760 atm = 0.9408 atm
3. Calculate the number of moles of nitrogen using the ideal gas equation:
PV = nRT
n = (PV) / RT
n = (0.9408 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00224 mol
4. Calculate the molar mass of nitrogen (N2 = 2*14.01 g/mol = 28.02 g/mol)
5. Calculate the mass of nitrogen in the compound:
Mass of nitrogen = 0.00224 mol * 28.02 g/mol = 0.0628 g
6. Calculate the percentage composition of nitrogen:
Percentage composition = (Mass of nitrogen / Mass of compound) * 100
Percentage composition = (0.0628 g / 0.35 g) * 100
Percentage composition ≈ 17.45%
Therefore, the percentage composition of nitrogen in the compound is approximately 17.45%. Hence, the correct answer is option B.
- Mass of organic compound = 0.35 g
- Volume of nitrogen collected = 55 mL
- Temperature = 300 K
- Pressure = 715 mm
- Aqueous tension at 300 K = 15 mm
Calculations:
1. Convert the volume of nitrogen collected to liters:
Volume of nitrogen = 55 mL = 0.055 L
2. Convert the pressure to atm:
Pressure = 715 mm = 715/760 atm = 0.9408 atm
3. Calculate the number of moles of nitrogen using the ideal gas equation:
PV = nRT
n = (PV) / RT
n = (0.9408 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00224 mol
4. Calculate the molar mass of nitrogen (N2 = 2*14.01 g/mol = 28.02 g/mol)
5. Calculate the mass of nitrogen in the compound:
Mass of nitrogen = 0.00224 mol * 28.02 g/mol = 0.0628 g
6. Calculate the percentage composition of nitrogen:
Percentage composition = (Mass of nitrogen / Mass of compound) * 100
Percentage composition = (0.0628 g / 0.35 g) * 100
Percentage composition ≈ 17.45%
Therefore, the percentage composition of nitrogen in the compound is approximately 17.45%. Hence, the correct answer is option B.
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In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer?
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In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer?.
In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Duma's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be : (Aqueous tension at 300 K = 15 mm) [2011]a)15.45b)16.45c)17.45d)14.45Correct answer is option 'B'. Can you explain this answer?.
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