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Which of the following compounds will exhibit cis-trans (geometrical) isomerism? [2009]
- a)Butanol
- b)2-Butyne
- c)2-Butenol
- d)2-Butene
Correct answer is option 'D'. Can you explain this answer?
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Which of the following compounds will exhibit cis-trans (geometrical) ...
Alkenes with double bonds cannot undergo free rotation and can have different geometrical shapes with two different groups on each end of the double bond.
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Which of the following compounds will exhibit cis-trans (geometrical) ...
Geometrical isomerism is a type of stereoisomerism in which molecules have the same molecular formula and sequence of bonded atoms, but differ in the spatial arrangement of their atoms due to restricted rotation around a double bond or ring.
Explanation:
a) Butanol: Butanol is a primary alcohol and does not have a double bond. Therefore, it cannot exhibit geometrical isomerism.
b) 2-Butyne: 2-Butyne is an alkyne compound and does not have a double bond. Therefore, it cannot exhibit geometrical isomerism.
c) 2-Butenol: 2-Butenol is an unsaturated alcohol and has a double bond. However, it cannot exhibit geometrical isomerism because the hydroxyl (-OH) group attached to the double bond does not allow restricted rotation.
d) 2-Butene: 2-Butene is an unsaturated hydrocarbon and has a double bond. It can exhibit geometrical isomerism because the double bond restricts rotation and the substituents on either side of the double bond can be arranged in different ways.
Therefore, the correct answer is option 'D' (2-Butene).
Explanation:
a) Butanol: Butanol is a primary alcohol and does not have a double bond. Therefore, it cannot exhibit geometrical isomerism.
b) 2-Butyne: 2-Butyne is an alkyne compound and does not have a double bond. Therefore, it cannot exhibit geometrical isomerism.
c) 2-Butenol: 2-Butenol is an unsaturated alcohol and has a double bond. However, it cannot exhibit geometrical isomerism because the hydroxyl (-OH) group attached to the double bond does not allow restricted rotation.
d) 2-Butene: 2-Butene is an unsaturated hydrocarbon and has a double bond. It can exhibit geometrical isomerism because the double bond restricts rotation and the substituents on either side of the double bond can be arranged in different ways.
Therefore, the correct answer is option 'D' (2-Butene).
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Which of the following compounds will exhibit cis-trans (geometrical) isomerism? [2009]a)Butanolb)2-Butynec)2-Butenold)2-ButeneCorrect answer is option 'D'. Can you explain this answer?
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