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For the reaction
X2O4(l) → 2XO2(g)
ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300K
Hence,ΔG is:
  • a)
    2.7 kcal
  • b)
    -2.7 kcal    
  • c)
    9.3 kcal
  • d)
    -9.3 kcal
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For the reactionX2O4(l)→ 2XO2(g)ΔU = 2.1 kcal,ΔS = 20...
Δn = 2-0 = 2
ΔH = ΔU + Δn(g)RT
= 2100 + 2*2*300 =3300 cal
ΔG = ΔH - TΔS
= 3300 - 300*20 = -2700 cal
= -2.700kcal
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For the reactionX2O4(l)→ 2XO2(g)ΔU = 2.1 kcal,ΔS = 20 cal K-1 at 300KHence,ΔG is:a)2.7 kcalb)-2.7 kcal c)9.3 kcald)-9.3 kcalCorrect answer is option 'B'. Can you explain this answer?
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For the reactionX2O4(l)→ 2XO2(g)ΔU = 2.1 kcal,ΔS = 20 cal K-1 at 300KHence,ΔG is:a)2.7 kcalb)-2.7 kcal c)9.3 kcald)-9.3 kcalCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about For the reactionX2O4(l)→ 2XO2(g)ΔU = 2.1 kcal,ΔS = 20 cal K-1 at 300KHence,ΔG is:a)2.7 kcalb)-2.7 kcal c)9.3 kcald)-9.3 kcalCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reactionX2O4(l)→ 2XO2(g)ΔU = 2.1 kcal,ΔS = 20 cal K-1 at 300KHence,ΔG is:a)2.7 kcalb)-2.7 kcal c)9.3 kcald)-9.3 kcalCorrect answer is option 'B'. Can you explain this answer?.
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