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A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution of
- a)Sodium hydroxide [1992]
- b)Sodium sulphate
- c)calcium chloride
- d)Sodium bicarbonate
Correct answer is option 'D'. Can you explain this answer?
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A is a lighter phenol and B is an aromatic carboxylic acid. Separation...
Carboxylic acids dissolve in NaHCO3 but phenols do not.
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A is a lighter phenol and B is an aromatic carboxylic acid. Separation...
Separation of A and B by using sodium bicarbonate solution:
Introduction:
The separation of a mixture of A (lighter phenol) and B (an aromatic carboxylic acid) can be carried out easily by using a solution of sodium bicarbonate. This method is based on the difference in their acidic and basic nature.
Procedure:
1. Add sodium bicarbonate solution to the mixture of A and B.
2. Shake the mixture well and observe the reaction.
3. Phenol (A) is less acidic and does not react with sodium bicarbonate, whereas carboxylic acid (B) is more acidic and reacts with sodium bicarbonate to form a salt.
4. The salt of carboxylic acid (B) is soluble in water and can be separated by filtration or decantation.
5. The phenol (A) remains unreacted and can be separated from the mixture.
Explanation:
Sodium bicarbonate acts as a weak base and reacts with acidic substances to neutralize them. In this case, carboxylic acid (B) is more acidic than phenol (A), and thus it reacts with sodium bicarbonate to form a salt. This salt is soluble in water and can be easily separated from the mixture by filtration or decantation. Phenol (A) remains unreacted and can be separated from the mixture.
Conclusion:
The separation of a mixture of A and B by using a solution of sodium bicarbonate is a simple and effective method. It is based on the difference in the acidic and basic nature of the two substances. This method can be used in the laboratory to isolate and purify different organic compounds.
Introduction:
The separation of a mixture of A (lighter phenol) and B (an aromatic carboxylic acid) can be carried out easily by using a solution of sodium bicarbonate. This method is based on the difference in their acidic and basic nature.
Procedure:
1. Add sodium bicarbonate solution to the mixture of A and B.
2. Shake the mixture well and observe the reaction.
3. Phenol (A) is less acidic and does not react with sodium bicarbonate, whereas carboxylic acid (B) is more acidic and reacts with sodium bicarbonate to form a salt.
4. The salt of carboxylic acid (B) is soluble in water and can be separated by filtration or decantation.
5. The phenol (A) remains unreacted and can be separated from the mixture.
Explanation:
Sodium bicarbonate acts as a weak base and reacts with acidic substances to neutralize them. In this case, carboxylic acid (B) is more acidic than phenol (A), and thus it reacts with sodium bicarbonate to form a salt. This salt is soluble in water and can be easily separated from the mixture by filtration or decantation. Phenol (A) remains unreacted and can be separated from the mixture.
Conclusion:
The separation of a mixture of A and B by using a solution of sodium bicarbonate is a simple and effective method. It is based on the difference in the acidic and basic nature of the two substances. This method can be used in the laboratory to isolate and purify different organic compounds.
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A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution ofa)Sodium hydroxide [1992]b)Sodium sulphatec)calcium chlorided)Sodium bicarbonateCorrect answer is option 'D'. Can you explain this answer?
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A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution ofa)Sodium hydroxide [1992]b)Sodium sulphatec)calcium chlorided)Sodium bicarbonateCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution ofa)Sodium hydroxide [1992]b)Sodium sulphatec)calcium chlorided)Sodium bicarbonateCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution ofa)Sodium hydroxide [1992]b)Sodium sulphatec)calcium chlorided)Sodium bicarbonateCorrect answer is option 'D'. Can you explain this answer?.
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