Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > A half-wave rectifier is used to charge a 12V... Start Learning for Free
A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode is
- a)136°
- b)120°
- c)173°
- d)137°
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A half-wave rectifier is used to charge a 12V battery through a resist...
Voltage at secondary winding of the coil is Vs
Voltage across diode
Vp → Vs max
Vn → 12 V
For conduction:
Vp > Vn
Therefore the diode is conducting for the period.
Therefore the diode is conducting for the period.
Most Upvoted Answer
A half-wave rectifier is used to charge a 12V battery through a resist...
The half-wave rectifier is a simple diode-based circuit that allows only one half of an alternating current (AC) waveform to pass through, while blocking the other half. In this case, the half-wave rectifier is being used to charge a 12V battery through a resistance.
When the AC voltage is positive, the diode allows the current to flow through and charges the battery. However, when the AC voltage is negative, the diode blocks the current flow, preventing the battery from discharging.
The resistance in the circuit limits the amount of current flowing through the diode and the battery, preventing excessive current and potential damage. It also helps to regulate the charging rate of the battery.
Overall, the half-wave rectifier charges the 12V battery by allowing only the positive half of the AC waveform to pass through, while the resistance limits the current flow and regulates the charging process.
When the AC voltage is positive, the diode allows the current to flow through and charges the battery. However, when the AC voltage is negative, the diode blocks the current flow, preventing the battery from discharging.
The resistance in the circuit limits the amount of current flowing through the diode and the battery, preventing excessive current and potential damage. It also helps to regulate the charging rate of the battery.
Overall, the half-wave rectifier charges the 12V battery by allowing only the positive half of the AC waveform to pass through, while the resistance limits the current flow and regulates the charging process.
 | Explore Courses for Electronics and Communication Engineering (ECE) exam |  |
Top Courses for Electronics and Communication Engineering (ECE)View all
Top Courses for Electronics and Communication Engineering (ECE)
Question Description
A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2026 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer?.
A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2026 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer?.
Solutions for A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A half-wave rectifier is used to charge a 12V battery through a resistance ‘R’. The input transformer is fed with 34 AC with turns ration 2 : 1. The conduction period of the diode isa)136°b)120°c)173°d)137°Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
| Explore Courses for Electronics and Communication Engineering (ECE) exam | |
Top Courses for Electronics and Communication Engineering (ECE)
Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
