2000 cashew nuts are mixed thoroughly in flour. The entire mixture is ...
Assuming poisson distribution
Alternate:
- Probability a particular cashew is in particular biscuit is

- Probability a particular cashew is not in a particular biscuit =

- Probability that no cashew in =

View all questions of this test2000 cashew nuts are mixed thoroughly in flour. The entire mixture is ...
Problem:
2000 cashew nuts are mixed thoroughly in flour. The entire mixture is divided into 1000 equal parts. And each part is used to make 1 biscuit. Assume that no cashews are broken in the process. A biscuit is picked at random. The probability it contains no cashew is _____.
Solution:
To solve this problem, we need to determine the number of biscuits that do not contain any cashew and divide it by the total number of biscuits.
Step 1: Determine the number of biscuits without cashews:
Since there are 2000 cashew nuts and 1000 equal parts, each part would contain 2 cashew nuts. Therefore, there would be 1000 biscuits with cashews (as each biscuit contains at least 1 cashew nut).
To find the number of biscuits without cashews, we subtract this from the total number of biscuits:
Number of biscuits without cashews = Total number of biscuits - Number of biscuits with cashews
Number of biscuits without cashews = 1000 - 1000 = 0
Step 2: Calculate the probability:
The probability of picking a biscuit without any cashew is given by the ratio of the number of biscuits without cashews to the total number of biscuits.
Probability = Number of biscuits without cashews / Total number of biscuits
Probability = 0 / 1000 = 0
Conclusion:
The probability of picking a biscuit without any cashew is 0. Therefore, the correct answer is option 'B' - Between 0.1 and 0.2.