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The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in  amperes) is
  • a)
    zero
  • b)
    0.02
  • c)
    0.03
  • d)
    0.036.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The circuit shown in the figure contains two diodes each with a forwar...
In the circuit, diode D1 is forward biased, while D2 is reverse biased. Therefore, current i (through D1 and 100Ω resistance) will be
Here, 50Ω is the resistance of D1 in forward biasing.
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The circuit shown in the figure contains two diodes each with a forwar...
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The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in amperes) isa)zerob)0.02c)0.03d)0.036.Correct answer is option 'B'. Can you explain this answer?
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The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in amperes) isa)zerob)0.02c)0.03d)0.036.Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in amperes) isa)zerob)0.02c)0.03d)0.036.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in amperes) isa)zerob)0.02c)0.03d)0.036.Correct answer is option 'B'. Can you explain this answer?.
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