The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) andrarr; 2BrCl(g) are 30kJ molandndash;1 and 105 JKandndash;1 molandndash;1 respectively.The temperature at which the reaction will be in equilibrium is [2006]a)273 Kb)450 Kc)300 Kd)285.7 KCorrect answer is option 'D'. Can you explain this answer?

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The enthalpy and entropy change for the reaction Br₂(l) + Cl₂(g) → 2BrCl(g) are 30kJ mol^–1 and 105 JK^–1 mol^–1respectively.The temperature at which the reaction will be in equilibrium is [2006]

a)
273 K
b)
450 K
c)
300 K
d)
285.7 K

Correct answer is option 'D'. Can you explain this answer?

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The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) &rarr...

We know that

ΔG = ΔH – TΔS

When the reaction is in equilibrium, ΔG = 0

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The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) → 2BrCl(g) are 30kJ mol–1 and 105 JK–1 mol–1 respectively.The temperature at which the reaction will be in equilibrium is [2006]a)273 Kb)450 Kc)300 Kd)285.7 KCorrect answer is option 'D'. Can you explain this answer?

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The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) → 2BrCl(g) are 30kJ mol–1 and 105 JK–1 mol–1 respectively.The temperature at which the reaction will be in equilibrium is [2006]a)273 Kb)450 Kc)300 Kd)285.7 KCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) → 2BrCl(g) are 30kJ mol–1 and 105 JK–1 mol–1 respectively.The temperature at which the reaction will be in equilibrium is [2006]a)273 Kb)450 Kc)300 Kd)285.7 KCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpy and entropy change for the reaction Br2(l) + Cl2(g) → 2BrCl(g) are 30kJ mol–1 and 105 JK–1 mol–1 respectively.The temperature at which the reaction will be in equilibrium is [2006]a)273 Kb)450 Kc)300 Kd)285.7 KCorrect answer is option 'D'. Can you explain this answer?.

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