The Van't Hoff factor or i-factor is defined as the ratio of the moles of particles in solution to the moles of the solute dissolved. It is used to calculate the colligative properties of solutions. In the case of an infinitely dilute solution of NaHSO4, the Van't Hoff factor can be determined as follows:

1. Determine the formula of NaHSO4

NaHSO4 is composed of one sodium ion (Na+), one hydrogen ion (H+), one sulfate ion (SO42-) and one hydrogen ion (H+). Therefore, the formula of NaHSO4 is NaHSO4.

2. Determine the number of particles in solution

In an infinitely dilute solution, the solute is completely dissociated. Therefore, NaHSO4 dissociates into its constituent ions:

NaHSO4 → Na+ + H+ + SO42-

Thus, the number of particles in solution is 3 (one Na+ ion, one H+ ion, and one SO42- ion).

3. Determine the moles of solute dissolved

In an infinitely dilute solution, the concentration of the solute is so low that it can be considered negligible. Therefore, the moles of solute dissolved can be assumed to be equal to the moles of particles in solution.

4. Calculate the Van't Hoff factor

The Van't Hoff factor for an infinitely dilute solution of NaHSO4 can be calculated as follows:

i-factor = (moles of particles in solution) / (moles of solute dissolved)

i-factor = 3 / 1

i-factor = 3

Therefore, the Van't Hoff factor for an infinitely dilute solution of NaHSO4 is 3.

In conclusion, the Van't Hoff factor for an infinitely dilute solution of NaHSO4 can be determined by calculating the ratio of the moles of particles in solution to the moles of solute dissolved. In this case, the i-factor is 3, which indicates that NaHSO4 dissociates into three particles in solution.