Class 11 Exam  >  Class 11 Questions  >  Given the following entropy values (in J K&nd... Start Learning for Free
Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g)  —→  2 HCl(g) is [1996]
  • a)
    +540.3
  • b)
    +727.0
  • c)
    –166.9
  • d)
    +19.8
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Given the following entropy values (in J K–1 mol–1) at 298...
Entropy change ΔS =  ΔSproduct - ΔSreactant  
= 2 (186.7) – (223 + 130.6)
 = 373.4 – 353.6
 = 19.8 JK–1 mol–1
View all questions of this test
Explore Courses for Class 11 exam

Similar Class 11 Doubts

Top Courses for Class 11

Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer?
Question Description
Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer?.
Solutions for Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Given the following entropy values (in J K–1 mol–1) at 298 K and 1 atm :H2(g) : 130.6, Cl2(g) : 223.0, HCl (g) : 186.7.The entropy change (in J K–1 mol– 1) for the reaction H2(g) + Cl 2(g) —→2 HCl(g) is [1996]a)+540.3b)+727.0c)–166.9d)+19.8Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev