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uniform rope of length 5m is on a smooth horizontal surface. it is being pulled by a horizontal force of 20N at one end . the ratio of tension at a distance of 2m from force end to tension at a distance of 2m from free end is a) 1÷! a) 1:)1a)1:1b)2:3c) 1:2d) 3:2
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uniform rope of length 5m is on a smooth horizontal surface...

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uniform rope of length 5m is on a smooth horizontal surface...
The problem states that a uniform rope of length 5m is placed on a smooth horizontal surface. It is being pulled by a horizontal force of 20N at one end. We are asked to find the ratio of tension at a distance of 2m from the force end to the tension at a distance of 2m from the free end.

To solve this problem, let's break it down into smaller steps:

1. Determine the tension at a distance of 2m from the force end:
Since the rope is being pulled by a horizontal force of 20N at one end, the tension at that end is also 20N. As we move along the rope towards the free end, the tension decreases due to the weight of the rope. At a distance of 2m from the force end, the tension can be calculated using the formula:

Tension = Force / Length * Distance
Tension = 20N / 5m * 2m
Tension = 8N

2. Determine the tension at a distance of 2m from the free end:
Since the force is being applied at the force end, the tension at the free end is 0N. As we move towards the force end, the tension increases linearly. At a distance of 2m from the free end, the tension can be calculated using the same formula:

Tension = Force / Length * Distance
Tension = 20N / 5m * 2m
Tension = 8N

3. Calculate the ratio of tension:
The ratio of tension at a distance of 2m from the force end to the tension at a distance of 2m from the free end is:

Ratio = Tension at force end / Tension at free end
Ratio = 8N / 8N
Ratio = 1:1

Therefore, the ratio of tension at a distance of 2m from the force end to the tension at a distance of 2m from the free end is 1:1.
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uniform rope of length 5m is on a smooth horizontal surface. it is being pulled by a horizontal force of 20N at one end . the ratio of tension at a distance of 2m from force end to tension at a distance of 2m from free end is a) 1÷! a) 1:)1a)1:1b)2:3c) 1:2d) 3:2 Related: 1st Law - NLM (Newton's Law of Motion), Class 11, Physics?
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uniform rope of length 5m is on a smooth horizontal surface. it is being pulled by a horizontal force of 20N at one end . the ratio of tension at a distance of 2m from force end to tension at a distance of 2m from free end is a) 1÷! a) 1:)1a)1:1b)2:3c) 1:2d) 3:2 Related: 1st Law - NLM (Newton's Law of Motion), Class 11, Physics? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about uniform rope of length 5m is on a smooth horizontal surface. it is being pulled by a horizontal force of 20N at one end . the ratio of tension at a distance of 2m from force end to tension at a distance of 2m from free end is a) 1÷! a) 1:)1a)1:1b)2:3c) 1:2d) 3:2 Related: 1st Law - NLM (Newton's Law of Motion), Class 11, Physics? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for uniform rope of length 5m is on a smooth horizontal surface. it is being pulled by a horizontal force of 20N at one end . the ratio of tension at a distance of 2m from force end to tension at a distance of 2m from free end is a) 1÷! a) 1:)1a)1:1b)2:3c) 1:2d) 3:2 Related: 1st Law - NLM (Newton's Law of Motion), Class 11, Physics?.
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