**Initial Projection**

The body is projected at an angle of 30° to the horizontal with a speed of 40 m/s. This means that the body is launched with an initial velocity that has two components: one along the horizontal direction and one along the vertical direction.

**Horizontal Component of Velocity**

The horizontal component of the initial velocity can be calculated using the formula:

Vx = V * cosθ

where Vx is the horizontal component of velocity, V is the magnitude of the initial velocity, and θ is the angle of projection.

Substituting the given values into the formula:

Vx = 40 m/s * cos(30°)
Vx = 40 m/s * √3/2
Vx = 40 * 1.732 / 2
Vx = 34.64 m/s

**Vertical Component of Velocity**

The vertical component of the initial velocity can be calculated using the formula:

Vy = V * sinθ

where Vy is the vertical component of velocity, V is the magnitude of the initial velocity, and θ is the angle of projection.

Substituting the given values into the formula:

Vy = 40 m/s * sin(30°)
Vy = 40 m/s * 1/2
Vy = 20 m/s

**Time of Flight**

The time of flight can be calculated using the formula:

T = (2 * Vy) / g

where T is the time of flight, Vy is the vertical component of velocity, and g is the acceleration due to gravity (approximately 9.8 m/s²).

Substituting the given values into the formula:

T = (2 * 20 m/s) / 9.8 m/s²
T = 40 m/s / 9.8 m/s²
T ≈ 4.08 s

**Angle with the Horizontal after 2 seconds**

To find the angle with the horizontal after 2 seconds, we need to determine the horizontal and vertical components of the velocity at that time.

Horizontal Component of Velocity at 2 seconds:

Vx = Vx (initial) = 34.64 m/s

Vertical Component of Velocity at 2 seconds:

Vy = Vy (initial) - g * t

where t is the time elapsed.

Substituting the values into the formula:

Vy = 20 m/s - 9.8 m/s² * 2 s
Vy = 20 m/s - 19.6 m/s
Vy = 0.4 m/s

The angle with the horizontal after 2 seconds can be calculated using the formula:

θ = arctan(Vy / Vx)

Substituting the values:

θ = arctan(0.4 m/s / 34.64 m/s)
θ ≈ arctan(0.0115)
θ ≈ 0.66°

Therefore, the angle with the horizontal after 2 seconds will be approximately 0.66°.

At 2 seconds
find out the velocity in X directions and y direction
now we know that tan theta is given by velecoty in y direction diveded by velecity in X direction .
here u go.

this method can be helpful in general cases as well.