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The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
  • a)
    three
  • b)
    five
  • c)
    infinite
  • d)
    zero
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The maximum number of possible interference maxima for slit-separation...
For constructive interference d sin θ = nλ
n = 0, 1,  – 1, 2,  – 2  hence five maxima are possible
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The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment isa)threeb)fivec)infinited)zeroCorrect answer is option 'B'. Can you explain this answer?
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