The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 andAring;, respectively. This indicates that [1999]a)bonding is 100% ionic in both the moleculesb)AB has more ionic bond character than CDc)AB has lesser ionic bond character than CDd)bonding is nearly covalent in both the moleculesCorrect answer is option 'C'. Can you explain this answer?

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The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that [1999]

a)
bonding is 100% ionic in both the molecules
b)
AB has more ionic bond character than CD
c)
AB has lesser ionic bond character than CD
d)
bonding is nearly covalent in both the molecules

Correct answer is option 'C'. Can you explain this answer?

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The dipole moments of diatomic molecules AB and CD are 10.41D and 10.2...

As dipole moment = electric charge × bond length D. M. of AB molecules = 4.8 x 10^-10 x 2.82 x10^-8= 13.53D
D.M. of CD molecules = 4.8 x10^-10 x 2.67 x10^-10= 12.81D
now% ionic character

then % ionic character in

% ionic character in

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The dipole moments of diatomic molecules AB and CD are 10.41D and 10.2...

To calculate the partial charge of each atom in the diatomic molecules, we can use the equation:

μ = charge × distance

where μ is the dipole moment, charge is the partial charge on each atom, and distance is the bond distance.

For molecule AB:
μ = 10.41 D
distance = 2.82 Å

Therefore, the partial charge on each atom in molecule AB can be calculated as:

charge = μ / distance
charge = 10.41 D / 2.82 Å

Converting D to Cm (Coulomb meter) and Å to meters:

1 D = 3.336 × 10^-30 Cm
1 Å = 1 × 10^-10 meters

charge = (10.41 D × 3.336 × 10^-30 Cm) / (2.82 × 10^-10 meters)
charge = 3.91 × 10^-19 C

So, the partial charge on each atom in molecule AB is 3.91 × 10^-19 C.

Similarly, for molecule CD:
μ = 10.27 D
distance = 2.67 Å

charge = μ / distance
charge = 10.27 D / 2.67 Å

Converting units:

charge = (10.27 D × 3.336 × 10^-30 Cm) / (2.67 × 10^-10 meters)
charge = 3.84 × 10^-19 C

Therefore, the partial charge on each atom in molecule CD is 3.84 × 10^-19 C.

Answered by Mohit Rajpoot · View profile

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The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that [1999]a)bonding is 100% ionic in both the moleculesb)AB has more ionic bond character than CDc)AB has lesser ionic bond character than CDd)bonding is nearly covalent in both the moleculesCorrect answer is option 'C'. Can you explain this answer?

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The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that [1999]a)bonding is 100% ionic in both the moleculesb)AB has more ionic bond character than CDc)AB has lesser ionic bond character than CDd)bonding is nearly covalent in both the moleculesCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that [1999]a)bonding is 100% ionic in both the moleculesb)AB has more ionic bond character than CDc)AB has lesser ionic bond character than CDd)bonding is nearly covalent in both the moleculesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This indicates that [1999]a)bonding is 100% ionic in both the moleculesb)AB has more ionic bond character than CDc)AB has lesser ionic bond character than CDd)bonding is nearly covalent in both the moleculesCorrect answer is option 'C'. Can you explain this answer?.

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