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If the latus rectum of an hyperbola be 8 and eccentricity be 3/√5 then the equation of the hyperbola is
- a)4x2 – 5y2 = 100
- b)5x2 – 4y2 = 100
- c)4x2 + 5y2 = 100
- d)5x2 + 4y2 = 100
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the latus rectum of an hyperbola be 8 and eccentricity be3/√5...
Give eccentricity of the hyperbola is, e= 3/(5)1/2
⇒ (b2)/(a2) = 4/5..(1)
And latus rectum is =2(b2)/a=8
⇒ b2/a=4…(2)
By (2)/(1) a=5
∴ b2=20
Hence required hyperbola is, (x2)/25−(y2)/20=1
⇒ 4x2−5y2 =100
⇒ (b2)/(a2) = 4/5..(1)
And latus rectum is =2(b2)/a=8
⇒ b2/a=4…(2)
By (2)/(1) a=5
∴ b2=20
Hence required hyperbola is, (x2)/25−(y2)/20=1
⇒ 4x2−5y2 =100
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If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer?
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If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer?.
If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the latus rectum of an hyperbola be 8 and eccentricity be3/√5then the equation of the hyperbola isa)4x2–5y2= 100b)5x2–4y2= 100c)4x2+ 5y2= 100d)5x2+ 4y2= 100Correct answer is option 'A'. Can you explain this answer?.
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