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In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer?.
Solutions for In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In the given circuit the capacitor (C) may be charged through resistance R by a battery V by closing switch S1. Also when S1 is opened and S2 is closed the capacitor is connected in series with inductor (L). Q. At the start, the capacitor was uncharged. When switch S1 is closed and S2 is kept open, the time constant of this circuit is τ. Which of the following is correcta)after time interval τ, charge on the capacitor is CV/2b)after time interval 2τ, charge on the capacitor of CV (1 – e–2)c)the work done by the voltage source will be half of the heat dissipated when the capacitor is fully chargedd)after time interval 2τ, charge on the capacitor is CV (1 – e–1)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.