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Proof of Heron's Formula for the Area of an Isosceles Triangle with Equal Sides

Given: Isosceles triangle with two equal sides of length 'b'

Herons's Formula:
The area of a triangle with sides of lengths a, b, and c is given by:
\[Area = \sqrt{s(s-a)(s-b)(s-c)}\]
where \(s = \frac{a+b+c}{2}\) is the semi-perimeter of the triangle.

Proof:

Step 1: Determine the lengths of the sides
Since the triangle is isosceles with two equal sides of length 'b', the third side will also be 'b'.

Step 2: Calculate the semi-perimeter
\[s = \frac{b + b + b}{2} = \frac{3b}{2}\]

Step 3: Substitute the values into Heron's Formula
\[Area = \sqrt{\frac{3b}{2} \left(\frac{3b}{2} - b\right)^2}\]
\[Area = \sqrt{\frac{3b}{2} \left(\frac{b}{2}\right)^2}\]
\[Area = \sqrt{\frac{3b}{2} \cdot \frac{b^2}{4}}\]
\[Area = \sqrt{\frac{3b^3}{8}}\]
\[Area = \frac{b}{2} \sqrt{3}\]

Conclusion:
The area of an isosceles triangle with two equal sides of length 'b' using Heron's Formula is \(\frac{b}{2} \sqrt{3}\).
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