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A particle of charge + q and mass m moving under the influence of a uniform electric field Eiˆ and uniform magnetic field B kˆ follows a trajectory from P to Q as shown in fig. The velocities at P and Q are viˆ and – 2vˆj . Which of the following statement (s) is/are correct ?
  • a)
  • b)
    Rate of work done by the electric field at 
  • c)
    Rate of work done by the electric field at P is zero
  • d)
    Rate of work done by both the fields at Q is zero
Correct answer is option 'A,B,D'. Can you explain this answer?
Most Upvoted Answer
A particle of charge + q and mass m moving under the influence of a un...
From Work Energy theorem
W=delta KE
= qE×2a=1/2m (4v^2-v^2)
E =3/4(mv^2/qa)

At P rate of work done by E field will be

= F.V=(qE) ×(V)cos 0 . ( vector)

=3/4 (mv^3/a)
At Q rate of work done
=F.V
=(qE)×(2v)cos 90=0

Therefore work done by magnetic field is zero .
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Community Answer
A particle of charge + q and mass m moving under the influence of a un...
Considering the activity from P to Q (Horizontal) u1 = v, v1 = 2v, s1 = 2a, Acc = A
⇒ 4v2 – v2 = 2A(2a)
Force acting in the horizontal direction is F = qE = mA
Rate of doing work at P
Rate of doing work by the magnetic field is throughout zero.The rate of doing work by electric field is zero at Q. Because at Q, the angle between force due to electric field and displacement is zero.
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A particle of charge + q and mass m moving under the influence of a uniform electric field Eiˆ and uniform magnetic field B kˆ follows a trajectory from P to Q as shown in fig. The velocities at P and Q are viˆ and – 2vˆj . Which of the following statement (s) is/are correct ?a)b)Rate of work done by the electric field at c)Rate of work done by the electric field at P is zerod)Rate of work done by both the fields at Q is zeroCorrect answer is option 'A,B,D'. Can you explain this answer?
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A particle of charge + q and mass m moving under the influence of a uniform electric field Eiˆ and uniform magnetic field B kˆ follows a trajectory from P to Q as shown in fig. The velocities at P and Q are viˆ and – 2vˆj . Which of the following statement (s) is/are correct ?a)b)Rate of work done by the electric field at c)Rate of work done by the electric field at P is zerod)Rate of work done by both the fields at Q is zeroCorrect answer is option 'A,B,D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle of charge + q and mass m moving under the influence of a uniform electric field Eiˆ and uniform magnetic field B kˆ follows a trajectory from P to Q as shown in fig. The velocities at P and Q are viˆ and – 2vˆj . Which of the following statement (s) is/are correct ?a)b)Rate of work done by the electric field at c)Rate of work done by the electric field at P is zerod)Rate of work done by both the fields at Q is zeroCorrect answer is option 'A,B,D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of charge + q and mass m moving under the influence of a uniform electric field Eiˆ and uniform magnetic field B kˆ follows a trajectory from P to Q as shown in fig. The velocities at P and Q are viˆ and – 2vˆj . Which of the following statement (s) is/are correct ?a)b)Rate of work done by the electric field at c)Rate of work done by the electric field at P is zerod)Rate of work done by both the fields at Q is zeroCorrect answer is option 'A,B,D'. Can you explain this answer?.
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