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A fair coin is tossed independently four times. The probability of the event “the number of time heads shown up is more than the number of times tails shown up” is 
  • a)
    1/16
  • b)
    1/8
  • c)
    1/4
  • d)
    5/16
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A fair coin is tossed independently four times. The probability of the...
Here we have to find
P(H, H, H, T) + P(H, H, H, H)
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Most Upvoted Answer
A fair coin is tossed independently four times. The probability of the...
Solution:
When a fair coin is tossed, there are possible outcomes for each toss: heads or tails. Therefore, for four tosses, there are possible outcomes.

Total number of outcomes = 2 × 2 × 2 × 2 = 16

Let's find the probability of the event that the number of times heads shown up is more than the number of times tails shown up.

Possible outcomes - H (heads), T (tails)
Since we want the number of times heads shown up to be more than the number of times tails shown up, the possible outcomes are:

HHHH
THHH
TTHH
TTTH

Therefore, the number of favorable outcomes = 4.

Probability of the event = (number of favorable outcomes) / (total number of outcomes) = 4/16 = 1/4

Therefore, the correct option is (c) 1/4.
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A fair coin is tossed independently four times. The probability of the event “the number of time heads shown up is more than the number of times tails shown up” isa)1/16b)1/8c)1/4d)5/16Correct answer is option 'D'. Can you explain this answer?
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