A fair coin is tossed independently four times. The probability of the...
Solution:
When a fair coin is tossed, there are possible outcomes for each toss: heads or tails. Therefore, for four tosses, there are possible outcomes.
Total number of outcomes = 2 × 2 × 2 × 2 = 16
Let's find the probability of the event that the number of times heads shown up is more than the number of times tails shown up.
Possible outcomes - H (heads), T (tails)
Since we want the number of times heads shown up to be more than the number of times tails shown up, the possible outcomes are:
HHHH
THHH
TTHH
TTTH
Therefore, the number of favorable outcomes = 4.
Probability of the event = (number of favorable outcomes) / (total number of outcomes) = 4/16 = 1/4
Therefore, the correct option is (c) 1/4.