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The measurement of the electron position if associated with an uncertainty in momentum, which is equal to 1 × 10–18 g cm s– 1 . The uncertainty in electron velocity is, [2008] (mass of an electron is 9 × 10– 28 g)
  • a)
    1 × 109 cm s–1
  • b)
    1 × 106 cm s–1
  • c)
    1 × 105 cm s–1
  • d)
    1 × 1011 cm s–1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The measurement of the electron position if associated with an uncerta...
The uncertainty principle states that there is a fundamental limit to the precision with which certain pairs of physical properties of a particle, such as position and momentum, can be measured simultaneously. According to the uncertainty principle, the product of the uncertainty in position (Δx) and the uncertainty in momentum (Δp) must be greater than or equal to a constant value.

Mathematically, the uncertainty principle is expressed as:

Δx * Δp ≥ h/4π

where h is the reduced Planck constant (approximately 6.626 x 10^-34 Joule-seconds).

In the given scenario, if the uncertainty in momentum (Δp) is equal to 1, then we can rewrite the uncertainty principle equation as:

Δx * 1 ≥ h/4π

Simplifying further, we get:

Δx ≥ h/4π

This means that the uncertainty in position (Δx) must be greater than or equal to the value of h/4π.
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Community Answer
The measurement of the electron position if associated with an uncerta...
∆p=m∆v
∆v=∆p/m
=1×10-18/9×10-28
=1×10 9cm s-1
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The measurement of the electron position if associated with an uncertainty in momentum, which is equal to 1 × 10–18 g cm s– 1 . The uncertainty in electron velocity is, [2008] (mass of an electron is 9 × 10– 28 g)a)1 × 109 cm s–1b)1 × 106 cm s–1c)1 × 105 cm s–1d)1 × 1011 cm s–1Correct answer is option 'A'. Can you explain this answer?
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